Use the normal distribution of SAT critical reading scores for which the meanis 506 and the standard deviation is 125. Assume the variable x is normallydistributed.(a) What percent of the SAT verbal scores are less than 675?(b) If 1000 SAT verbal scores are randomly selected, about how manywould you expect to be greater than 525?Click to view page 1 of the standard normal table.Click to view page 2 of the standard normal table.(a) Approximately % of the SAT verbal scores are less than 675.(Round to two decimal places as needed.)

X~N( μ , ?)μ=506 , ?=125Z-score =( x - μ )/?

Answered: e the normal distribution of SAT…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean is 146 and the standard deviation is 35. A score of 41 is how many z-scores below the mean?
8
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0.05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). E Click the icon to view the data. In this example, Hg is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 H,: Ha #0 O B. Ho: Ha #0 H1: Hd =0 O C. Ho: Ha #0 O D. Ho: Ha = 0 H1: Hd 0
Ch 8 FRQ ( The distribution of average speeds of the top 53 drivers in NASCAR is roughly symmetric, unimodal, and bell-shaped, with a mean of 184.8 mph and a standard deviation of 7.2 mph. In the space above, draw a Normal Curve, from z=-3 to z=+3. Draw vertical lines at the mean and each whole number standard deviation above and below the mean. Write two rows of numbers under the base line; one row with the number of standard deviations above and below the mean (z-scores), and a row under that with the actual values for this problem. ] What percent of drivers would you expect to have speeds below 199.2 mph ? Show all work. s] What is the area under the curve to the left of a speed of 170.4mph Show all work. What is the probability that a driver selected at random will have a speed below 172.0 mph ? Show all work. B] What percent of drivers would you expect to have a speed above 177.0 mph ? Show all work. How many drivers would you expect to have speeds between 170.4 mph and 177.0 mph…
The average number of words in a romance novel is 64,289 and the standard deviation is 17,272. Assume the distribution is normal. Let X be the number of words in a randomly selected romance novel. Round all answers to 4 decimal places where possible.b. Find the proportion of all novels that are between 62,562 and 79,834 words. ________________c. The 85th percentile for novels is words. (Round to the nearest word) ________________d. The middle 70% of romance novels have from _______ words to _______ words. (Round to the nearest word)
In a normal curve, the percentage of the scores between one and two standard deviations above the mean is approximately __________. Select one: a. 14% b. 50% c. It is impossible to tell. d. 2% Clear my choice
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Standard deviation CV = • 100% Mean E Click the icon to view the data sets. Data Table C/heights = 5.0 % (Round to the nearest tenth as needed.) Heights Weights CVweights =% (Round to the nearest tenth as needed.) 68 181 77 169 72 167 72 207 71 177 70 175 78 185 69 186 67 221 70 216 67 209 73 206
The data in the table is points scored by a basketball team in a certain period of time. Use the data in the table to answer the bulleted statements.
2b please
The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you conclude? Heights Weights77 19379 20569 22379 22077 22572 17965 20173 21071 19670 20475 21379 209 CV heights= % CV weights = % what can you conclude?
When we describe our data, we list three basic properties of the frequency distribution. One of them is the shape of the distribution. The other two are: the independent and dependent variables a measure of central tendency and a measure of variability the variance and the standard deviation whether it is normal or skewed
K A data set lists weights (lb) of plastic discarded by households. The highest weight is 5.26 lb, the mean of all of the weights is x=2.312 lb, and the standard deviation of the weights is s = 1.118 lb. a. What is the difference between the weight of 5.26 lb and the mean of the weights? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the weight of 5.26 lb to a z score. d. If we consider weights that convert to z scores between 2 and 2 to be neither significantly low nor significantly high, is the weight of 5.26 lb significant? a. The difference islb. (Type an integer or a decimal. Do not round.) View an example Get more help. ... Clear all Check answer Incor

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