The prices of a 16 oz latte are not normally distributed, with µ = $4.00 and o= $0.75. Suppose a random sample of n = 90 willbe selected, the price will be recorded for each latte, and the sample mean will be computed.Based on the information provided, which option applies to the distribution of possible sample mean values?n The distribution of all possible sample mean values is normal because the population distribution of responses isnormal.The distribution of all possible sample mean values is unknown because the sample size is not large enough and thepopulation distribution of responses is not normal.The distribution of all possible sample mean values is approximately normal because the sample size n is largeenough (at least 10 successes and at least 10 failures).The distribution of all possible sample mean values is approximately normal because the sample size n is largeenough (larger than 25).

Answered: prices of a 16 oz latte are not…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A pharmaceutical company makes tranquilizers. It is assumed that the distribution for the length of time they last is approximately normal. Researchers in a hospital used the drug on a random sample of 9 patients. The effective period of the tranquilizer for each patient (in hours) was as follows: 2.5; 2.8; 3.1; 2.3; 2.3; 2.2; 2.8; 2.1; and 2.4. 1.Which distribution should you use for this problem? (Enter your answer in the form z or tdf where df is the degrees of freedom.) 2. Construct a 95% confidence interval for the population mean length of time. (i) State the confidence interval. (Round your answers to two decimal places.) ( , ) (iii) Calculate the error bound. (Round your answer to two decimal places.)
A pharmaceutical company makes tranquilizers. It is assumed that the distribution for the length of time they last is approximately normal. Researchers in a hospital used the drug on a random sample of 9 patients. The effective period of the tranquilizer for each patient (in hours) was as follows: 2.5; 2.9; 3.1; 2.3; 2.3; 2.2; 2.8; 2.1; and 2.4.
Solve part a,b and c of practice question #2. Please and thank you.
answer d)

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