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Suppose one photon has a wavelength of 3260 nanometers while a second photon has a wavelength 1/5 as large. What is the ratio of the energy of the second photon divided by the first photon?

Suppose one photon has a wavelength of 3260 nanometers while a second photon has a wavelength 1/5 as large. What is the ratio of the energy of the second photon divided by the first photon?

Applications and Investigations in Earth Science (9th Edition)
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
Section: Chapter Questions
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**Problem Statement: Photon Energy Ratio Calculation** Suppose one photon has a wavelength of 3260 nanometers while a second photon has a wavelength \( \frac{1}{5} \) as large. What is the ratio of the energy of the second photon divided by the first photon? --- **Explanation for Educators:** This problem involves understanding the relationship between the wavelength of a photon and its energy. According to the photon energy equation \( E = \frac{hc}{\lambda} \), where \( E \) is the energy, \( h \) is Planck's constant, \( c \) is the speed of light, and \( \lambda \) is the wavelength. A smaller wavelength results in higher energy. This exercise helps students practice using this relationship to compare the energies of photons with different wavelengths.
Transcribed Image Text:**Problem Statement: Photon Energy Ratio Calculation** Suppose one photon has a wavelength of 3260 nanometers while a second photon has a wavelength \( \frac{1}{5} \) as large. What is the ratio of the energy of the second photon divided by the first photon? --- **Explanation for Educators:** This problem involves understanding the relationship between the wavelength of a photon and its energy. According to the photon energy equation \( E = \frac{hc}{\lambda} \), where \( E \) is the energy, \( h \) is Planck's constant, \( c \) is the speed of light, and \( \lambda \) is the wavelength. A smaller wavelength results in higher energy. This exercise helps students practice using this relationship to compare the energies of photons with different wavelengths.
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Wavelength is small then frequency high and when frequency high energy will be more so second photon has more energy 5  times to first

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