A quantum of electromagnetic radiation has an energy of 1.02 keV. What is its wavelength? The speed of light is 2.99792 x 10° m/s, and Planck's constant is 6.62607 × 10-34 Answer in units of nm. J S.
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- 25. A photon has a frequency of 1.14 x 10^15 Hz. What is the energy of the photon? Use the formula E = hf, where E is energy in Joules, h is Planck's constant = 6.62 x 10^-34 J/s, and f is frequency (Hz). 5.82 x 10^-49J 8.77 x 10^-16 J 7.55 x 10^-19 J 1.09 x 10^-12 J wwwwww4. In an experiment on the photoelectric effect, a metal is illuminated by visible light of different wavelengths. A photoelectron has a maximum kinetic energy of 0.9 eV when red light of wavelength 640 nm is used. With blue light of wavelength 420 nm, the maximum kinetic energy of the photoelectron is 1.9 eV. Use this information to calculate an experimental value for the Planck constant h. [A. What is the energy of a 194.0MHz radio-frequency photon? B. What is the energy of a visible-light photon with a wavelength of 611.0nm? C. What is the energy of an x-ray photon with a wavelength of 0.236nm?
- 14 A photon with a frequency of 5.02 x 10Hz is absorbed by an excited hydrogen atom which causes the electron to be ejected from the atom, forming an ion. Determine the energy of the photon, (Speed of light = 3.0 x 108 m/s, mass of proton = 1.0078250, mass of neutron = 1.008665U, 1U = 931.5- Planck's constant = 6.63 x 10-34 Js, mass of electron = 9.11 x 10-31 kg, Rydberg constant = 1.1 x 107 m. eV = 1.6 × 10-¹9 C). MeV Select one: O O a. 1.2 eV b. 2.1 eV c. 3.2 eV d. 4.1 eVWhich of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108 m/s. a. 1.89/hxc b. hc/1.89 c. 1.89 x h x c d. (1.51 + 3.4)/hc e. hc/3.43.1. What is the de Broglie wavelength of an electron that has been accelerated through a potential difference of AV = 150 V?
- A) Find the wavelength of a photon that has energy of 27 eVeV. Express your answer with the appropriate units. B) Find the wavelength of an electron that has energy of 27 eVeV. (The energy of the electron is its kinetic energy.) Express your answer with the appropriate units.Visible light falls into wavelength ranges of 400-700 nm, for which 1 m=1×109 nm The energy and wavelength of light are related by the equationE=hcλ where E is energy in Joules, h is Planck's constant ( 6.626×10−34 J-s ), c is the speed of light ( 2.998×108 m/s), and λ is the wavelength in m. If a visible light photon has a wavelength of 632.3 nm, what is the energy of the photon (in J)?A photon of light has a frequency of 5.00 x 1014 Hz. If the frequency of the photon was doubled then which of these would happen to the energy of this photon? a. it would become one-fourth as much b. it would become half as much c. it would double d. it would quadruple e. it would triple