A 610 keV gamma ray is incident on an electron at rest. If the scattered photon has a scattering angle of 112° with respect to the direction of the incident photon, determine the following.(a) Energy (in keV) of the scattered photon2.094How can you determine the wavelength and hence energy of the scattered photon? keV(b) Kinetic energy (in keV) of the scattered electron40.2How is the energy of the scattered electron related to the energy of the incident and scattered photons? ke(c) Recoil angle (in degrees) of the scattered electron112xIs momentum conserved during this process? How can you determine the momentum of the scattered photon and electron?°

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