Suppose in 2011 a survey of 1037 workers in the city of Vancouver found that 225 used public transport to commute to work. Part (a) Estimate the percentage of workers in Vancouver who use public transport to commute to work. Give your answer in percentages (without the percentage sign, and to four significant digits). Part (b) Find a 95% confidence interval for the percentage of workers in Vancouver using public transport to commute to work. Use the sample proportion in your estimate of the standard error. Provide the upper and lower bounds for your confidence interval. Give your answer in percentages (without the percentage sign, and to four significant digits) (

Suppose in 2011 a survey of 1037 workers in the city of Vancouver found that 225 used public transport to commute to work. Part (a) Estimate the percentage of workers in Vancouver who use public transport to commute to work. Give your answer in percentages (without the percentage sign, and to four significant digits). Part (b) Find a 95% confidence interval for the percentage of workers in Vancouver using public transport to commute to work. Use the sample proportion in your estimate of the standard error. Provide the upper and lower bounds for your confidence interval. Give your answer in percentages (without the percentage sign, and to four significant digits) (

Name: Suppose in 2011 a survey of 1037 workers in the cityof Vancouver foun
Uploaded: 2022-12-08T14:54:05.000Z
Channel: Bartleby
Description: Suppose in 2011 a survey of 1037 workers in the cityof Vancouver found that 225 used public transport tocommute to work.Part (a) Estimate the percentage of workers inVancouver who use public transport to commute towork. Give your answer in percentag

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: In a survey of 2316 adults, 701 say they believe in UFOs. Construct a 90 % confidence interval…

A: The objective of this question is to construct a 90% confidence interval for the population…

Q: Suppose a consumer advocacy group wants to conduct a survey to find if the proportion of consumers…

Q: Students at a certain college were asked if they have a car. After surveying 823 students, it was…

A: We know that a margin of error tells us how many percentage points our results will differ from the…

Q: Suppose in 2011 a survey of 1067 workers in the city of Calgary found that 183 used public transport…

A: It is given that sample size (n) is 1,067 and x is 183.

Q: adults in a recent year, 742 made a New Year's resolution to eat healthier. Construct 90% and…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: A television station surveys 200 customers and finds that 23% of customers watch the evening news.…

A: Given data n=200 p=23% confidence level=99%

Q: In a survey of 2113 adults in a recent year, 741 made a New Year's resolution to eat healthier.…

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: Suppose in a recent poll of 1250 randomly selected Californians who took vacations, 132 of them…

Q: In a survey of 3985 adults, 711 oppose allowing transgender students to use the bathrooms of the…

A: Given, n=3985 x=711 To find a confidence interval for a population proportion.

Q: In a survey of 4008 adults, 728 oppose allowing transgender students to use the bathrooms of the…

Q: To devise effective marketing strategies it is helpful to know the characteristics of your…

A: Givensample size(n)=932x=543p^ =xn=543932=0.5826Confidence level(c)=95%α=1-0.95=0.05α2=0.025critical…

Q: Heather runs a successful lawn-mowing business. She would like to estimate the true mean amount of…

A: Given that Sample size n =30 90 % confidence interval is (40 , 55)

Q: In your work for a real estate company, you find that in a sample of 1762 home buyers, 722 found…

A: Givenx=722n=1762p^=7221762p^=0.4098α=1-0.98=0.02α2=0.01zc=z0.01=2.3263 (from z-table)

Q: A survey was conducted that asked 984 people how many books they had read in the past year. Results…

A: Sample size is, Sample mean is, Sample standard deviation is, Confidence level is The objective is…

Q: In a random sample of 500 adults, 410 described themselves as vegetarians. Construct a 95%…

A: We have been provided with the following information about the adults who describe themselves as…

Q: According the the U.S. Census bureau, the percentage of Santa Ana residents living in poverty is…

A: Given: p^1=0.177p^2=0.133n1=1200n2=1500

Q: A television sports commentator wants to estimate the proportion of citizens who "follow…

A: Solution: From the given information, confidence level is 0.96 and E=0.02.

Q: n a survey of 4026 adults, 708 oppose allowing transgender students to use the bathrooms of the…

Q: Emma wants to estimate the percentage of people who use public transportation in a city. She surveys…

A: Obtain the margin of error. The margin of error is obtained below: The formula for the margin of…

Q: business conducts a random sample of 89 of its customers and find that 44 of them think the company…

Q: A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll,…

A: Given , n = 1008 x = 598

Q: Suppose in 2011 a survey of 1064 workers in the city of Calgary found that 184 used public transport…

A: From the provided information, Sample size (n) = 1064 From which 184 used public transport to…

Q: aOf 500 random people surveyed, 72 were smokers. Find the 80% confidence interval for smokers.

A: It is given that, Out of 500 random people surveyed, 72 were smokers. So, the portion of the…

Q: Cough and Headache At the 98% confidence level, should be nurse inform the managers that their…

A: The number of sampled patients that complained of cough and headache, n=230.The number of patients…

Q: 2. Construct a 95% confidence interval to estimate the proportion of Wingate female students that…

A: total number of female students =181 number of students who are left handed=15

Q: In a survey of 1000 people, 850 said they would not to travel to Disney World this summer. Construct…

A: Given: n=1000 and x=850 Then,p^=xn=8501000=0.85

Q: n a survey of 3932 adults, 718 oppose allowing transgender students to use the bathrooms of the…

Q: In a survey of 3983 adults, 747 oppose allowing transgender students to use the bathrooms of the…

Q: In a sample of 300 people, 48 identified as dog owners. Construct a 99% confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of people who are dog owners. The 99%…

Q: A researcher wanted to compare the percentages of men and women who play the lottery. They randomly…

Q: In a random sample of 600 adults, 270 described themselves as vegetarians. Construct a 99%…

A: In a random sample of 600 adults, 270 described themselves as vegetarians.

Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…

Q: A survey showed 980 of 1500 adult respondents believe in global warming. Construct a 95% confidence…

Q: If a 90%, a 95% and a 99% confidence interval are foung for a population mean, describe how the 3…

A: Population mean CI for known population standard deviation is, CI=x¯±Zσnwhere,σ=population standard…

Q: 3. Aresearcher wants to estimate the daily expenses of college students. He wants a 99% confidence…

Q: n a recent Zogby International Poll, nine of 48 respondents rated the likelihood of a terrorist…

A: Given that : x = 9 n = 48

Q: Out of 42738 freshmen entering the State University system, 27298 of them need to take remedial…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages. Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

Practice Pack

OFFON

Suppose in 2011 a survey of 1037 workers in the city
of Vancouver found that 225 used public transport to
commute to work.
Part (a) Estimate the percentage of workers in
Vancouver who use public transport to commute to
work. Give your answer in percentages (without the
percentage sign, and to four significant digits).
Part (b) Find a 95% confidence interval for the
percentage of workers in Vancouver using public
transport to commute to work. Use the sample
proportion in your estimate of the standard error.
Provide the upper and lower bounds for your
confidence interval. Give your answer in percentages
(without the percentage sign, and to four significant
digits) (

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

Includes step-by-step video

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Learn your way

Includes step-by-step video

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.

Similar questions

A survey was conducted that asked 1004 people how many books they had read in the past year. results indicated that x=13.6 books and s=16.6 books. construct a 95% confidence interval for the mean number of books people read interpret the interval. construct a 95% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice.
One year’s survey results, of 1525 respondents, 846 said that they expected difficulty finding a job. Find a 95% confidence interval for the population proportion of students who expect difficulty finding a job.
In a survey of 952 respondents, 620 of them voted in a recent election. Find a 95% confidence interval estimate for the true population proportion that voted in this election.
In a survey of 500 students, 327 said they were planning to stay in town for the holidays. What is the point estimate for the proportion of students staying home for the holidays? Construct the 95% confidence interval for the proportion of students staying home for the holidays. Assume all requirements have been met.
When 370 junior college students were surveyed, 145 said they have a passport. Construct a 95% confidence interval for the proportion of junior college students that have a passport. Round to 2 decimal places.
Suppose you calculate a 99% confidence interval of 14.71 to 21.64. Determine the margin of error.
You want to estimate the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work. You took an SRS of 7 businesses and collected the following data for number of complaints in a year: men 1 3 2 4 6 3 5 women 8 7 6 3 5 12 15 Create a 90% confidence interval for the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work (in a year). You must do this using table C. If this is a 2 sample interval, be sure to specify who is population 1 and who is population 2. If this is a matched pairs interval, be sure to state the order you subtracted your data. Once you create your interval, give a sentence explaining the meaning of the interval (what the numbers in the interval mean, NOT the meaning of 95%) in context of this problem. Round to any appropriate number of decimals.
10. Several years ago, 51% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,075 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,075 surveyed, 472 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed. What are the null and alternative hypotheses? Ho: p (1) versus H1: p (2) (Round to two decimal places as needed.) Use technology to find the 99% confidence interval. The lower bound is The upper bound is (Round to two decimal places as needed.) What is the correct conclusion? O A. Since the interval contains the proportion stated in the null hypothesis, there is insufficient evidence that parents' att O B. Since the interval contains the proportion stated in the null hypothesis, there is sufficient…
Suppose you calculate a 99% confidence interval of 14.1 to 21.84. Determine the margin of error.
In a survey of 2033 adults in a recent year, 735 made a New Year's resolution to eat healthier. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals.
Melissa wants to estimate the proportion of adults in the U.S. who own a gun. To do so, she surveys 45 adults, and finds that 14 own a gun. Construct a 95% confidence interval to estimate the proportion of all adults in the U.S. who own a gun. Write a conclusion sentence.
A study was designed to estimate the prevalence of smoking in Harris county. Of 675 people sampled, 522 were non-smokers. What is the 95% Confidence Interval estimate for the prevalence? (74.2%, 80.5%) (19.5%, 25.8%) (.19, .25)