Suppose in a recent poll of 1250 randomly selected Californians who took vacations, 132 of them reported visiting theme parks. Use the four-step process to find a 95% confidence interval for the proportion of Californians who visit a theme park while on vacation. Round final calculations to the nearest tenth of a percent.

Q: Ninety-four percent of students said that cash is their top choice for a graduation gift. If 75…

A: It is given that sample size (n) is 75and the sample proportion value is 0.94.

Q: You're considering going to graduate school, and you would like to know how many people would…

A:

Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…

A: Answer x =466n =804Confidence interval =95%

Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: In a survey of 3084 adults aged 57 through 85 years it was found that 81.9% of them used at least…

A: Given : Sample Size, n = 3084 confidence level,c=0.9 Significance level, α…

Q: Over the break, you do some reasearch. In a random sample of 250 U.S. adults, 56% said they ate…

A:

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: It is given that Sample size n = 250 Number of students receiving scholarship, X = 70 The critical…

Q: Public Policy Polling recently conducted a survey asking adults across the U.S. about music…

A: Given data  N = 571 X = 80 99% confidence interval

Q: In a survey of 2000 adults in a recent​ year, 708 made a New​ Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: A medical director needs to know the proportion of patients who have a single bed in their room. A…

A: It is given that sample size (n) is 200 and p-hat value is 0.59.

Q: In a survey of 2282​ adults, 749 say they believe in UFOs. Construct a 90% confidence interval for…

A:

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: In a survey of 2004 adults in a recent​ year, 717 made a New​ Year's resolution to eat healthier.…

A:

Q: A random sample of 900 car owners in a particular city found 252 car owners who received a speeding…

A: Given,n=900x=252p^=xnp^=252900=0.281-p^=1-0.28=0.72α=1-0.95=0.05α2=0.025Z0.025 =1.96   (from…

Q: To devise effective marketing strategies it is helpful to know the characteristics of your…

A: Givensample size(n)=932x=543p^ =xn=543932=0.5826Confidence level(c)=95%α=1-0.95=0.05α2=0.025critical…

Q: A department chair wanted to know whose students performed better on a common pass/fail final exam:…

A: p1 :  proportion of students passed in smith's  class p2 :  proportion of students passed in Jones's…

Q: Heather runs a successful lawn-mowing business. She would like to estimate the true mean amount of…

A: Given that  Sample size n =30 90 % confidence interval is (40 , 55)

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: In a sample of 110 adults, 76 had children. Construct a 95% confidence interval for the true…

A: It is given that, in a sample of 110 adults, 76 had children. It is needed to find a 95% confidence…

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: A research group asked 4488 Americans how they fall asleep, and 536 of them fall asleep on their…

A: Obtain the 90% confidence interval for the percentage of all Americans who fall asleep on their…

Q: A survey was conducted that asked 984 people how many books they had read in the past year. Results…

A: Sample size is, Sample mean is, Sample standard deviation is, Confidence level is The objective is…

Q: According the the U.S. Census bureau, the percentage of Santa Ana residents living in poverty is…

A: Given: p^1=0.177p^2=0.133n1=1200n2=1500

Q: A Pew Internet poll asked 4272 U.S. adults about their use of smart watches and fitness trackers. A…

A: Given,n=4272X=897

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: Find the point estimate of the percentage of men who have red/green color blindness. b. Find a 90%…

A: Given that sample size n = 80 Number of men who have red/green color blindness, X = 7 At 90%…

Q: According to Thomson Financial, through January 25, 2018, the majority of companies reported profits…

A: The sample proportion of companies showed beat estimates is, p^=104162=0.6420 The sample proportion…

Q: An interactive poll found that 397 of 2,391 adults aged 18 or older have at least one tattoo. A.…

A: Given data: Sample size (n) = 2391 x = 397 adults To construct: 1.95 % confidence interval 2.98%…

Q: A random sample of 2000 car owners in a particular city found 740 car owners who received a speeding…

A:

Q: To assess the proportion of the readers of a magazine being professional, a random sample of 1000…

A: Given that the random sample of 1000 readers is selected and 660 are found to be professionals. That…

Q: What is the confidence interval? Select the correct choice below and, if necessary, fill in the…

A: Mean = 56.64 Standard deviation = 14.598 n=100

Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…

A:

Q: What is the minimum number of free throws Shaq would have to attempt so that it would meet the…

A:

Q: In a survey of 2013 adults in a recent​ year, 731 made a New​ Year's resolution to eat healthier.…

A:

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: Angela is trying to figure out the sample size for the data set she wants to collect. She is…

A: The larger the sample size, the less will be the value of standard error. Therefore, the range of…

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: psychologist wanted to know if students in her class were more likely to cheat if they were low…

A: ANSWER:After reviewing the data set, we need to determine whether the observed patterns support or…