### Poverty Rate Comparison Between Santa Ana and IrvineAccording to the U.S. Census Bureau, the percentage of Santa Ana residents living in poverty is 17.7%, and the percentage of Irvine residents living in poverty is 13.3%. Suppose that the sample sizes were 1200 for the Santa Ana group and 1500 for the Irvine group. Use the survey data to calculate and interpret a 90% confidence interval for the difference in the proportion living in poverty between Santa Ana and Irvine.

Given: p^1=0.177p^2=0.133n1=1200n2=1500

Answered: According the the U.S. Census bureau,…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

A sample of 1,000 employees in an international company was taken to estimate the average expenditure. The sample mean is $520, while the sample std dev is $156. Calculate the 90% and the 99.9% confidence intervals. Explain your results
The daily salaries of security guards for 10 security agencies are as follows: 350, ₱400, 375, 420, 500,470, 380, 450, 520, and 460. What is the point estimate for themean? Find the 95% confidence interval of the mean for the salaries of securityguards in the area.
A contributor for the local newspaper is writing an article for the weekly fitness section. To prepare for the story, she conducts a study to compare the exercise habits of people who exercise in the morning to the exercise habits of people who work out in the afternoon or evening. She selects three different health centers from which to draw her samples. The 57 people she sampled who work out in the morning have a mean of 4.8 hours of exercise each week. The 56 people surveyed who exercise in the afternoon or evening have a mean of 4.2 hours of exercise each week. Assume that the weekly exercise times have a population standard deviation of 0.8 hours for people who exercise in the morning and 0.3 hours for people who exercise in the afternoon or evening. Let Population 1 be people who exercise in the morning and Population 2 be people who exercise in the afternoon or evening. Step 1 of 2: Construct a 95 % confidence interval for the true difference between the mean amounts of time…
A high school counselor is interested in determining factors that contribute to high school drop out rates. One factor of interest to her is whether kids who are involved in team sports as children are less likely to drop out of high school. She surveys 41 high school graduates and finds that 30 were involved in team sports as children. She then surveys 38 high school dropouts and finds that 23 were involved in team sports as children. Construct and interpret a 90% confidence interval for the true difference between the proportions of high school graduates and dropouts who participated in team sports as children. Does this data suggest that there is a difference between these proportions at this level of confidence? Correctly round your results to the nearest tenth of a percent (one decimal place) in the intepretation of your interval.
Refer to the accompanying data set of 20 randomly selected presidents. Treat the data as a sample and find the proportion of presidents who were taller than their opponents. Use that result to construct a 95% confidence interval estimate of the population percentage. Based on the result, does it appear that greater height is an advantage for presidential candidates? Why or why not? Click the icon to view the table of heights. Construct a 95% confidence interval estimate of the percentage of presidents who were taller than their opponents. (Round to one decimal place as needed.) McKinley 170 178Lincoln 193 188Reagan 185 177Taft 182 178Harrison 173 168Van Buren 168 180Harding 183 178Eisenhower 179 178Taylor 173 174Garfield 183 187J. Kennedy 183 182Harrison 168 180J. Q. Adams 171 191Clinton 188 188Nixon 182 180Johnson 192 180Hoover 182 180T. Roosevelt 178 175Buchanan 183…
If 64% of a sample of 550 people leaving a shopping mall claims to have spent over $25 create and interpret a 95% confidence interval estimate for the proportion of shopping mall customers who spend over $25
What Z score would be used to construct a 90% confidence level? Is it ... a. 1.65 b. 2.33 c. 2.58 d. 1.96
Angela is trying to figure out the sample size for the data set she wants to collect. She is considering using a 90% or a 99% confidence level. Explain to Angela the impact the different levels will have on her sample size.
Students at a certain college were asked if they have a car. After surveying 601 students, it was found that 40.3% of them have a car. The margin of error was 4% with a 95% confidence level. What does this margin of error tell you about the percentage of students at that college who have a car? We can be 95% confident that somewhere between % and % of the students at that college have a car.
In a survey of 3116 adults aged 57 through 85 years, it was found that 86.2% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3116 subjects used at least one prescription medication? b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. c. What do the results tell us about the proportion of college students who use at least one prescription medication? A. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b). B. The results tell us that, with 90% confidence, the probability that a college student uses at least one prescription medication is in the interval found in part (b). C. The results tell us that, with 90% confidence, the true proportion of college students who use at…
b. In the year 2000, a survey of 1171 U.S. adults were asked who they felt was the greatest President. Of those surveyed, 397 reported that Abraham Lincoln was the greatest President. Use this data to construct a 99% confidence interval for the population proportion of all U.S. adults who would say that Abraham Lincoln was the greatest president before the year 2000. Answer using decimals and round to four decimal places
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=935 and x=561 who said "yes." Use a 95% confidence level.

SEE MORE QUESTIONS

Recommended textbooks for you

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability (10th Edition)

Probability

ISBN:

9780134753119

Author:

Sheldon Ross

Publisher:

PEARSON

A First Course in Probability

Probability

ISBN:

9780321794772

Author:

Sheldon Ross

Publisher:

PEARSON

SEE MORE TEXTBOOKS