Suppose following simplex table: 2 3 1 -1 0 0 -100 x1 x2 x3 x4 x5 x6 x7 b x5 0 7/2 0 0 3/2 1 1/2 -3/2 14 x3 1 5/2 0 1 1/2 0 1/2 1/2 13 x2 3 0 1 0 1 0 0 1 17 Z - C We can say, that: Select one: The solution is not optimal. The solution is optimal. The solution can be the initial solution.

Suppose following simplex table: 2 3 1 -1 0 0 -100 x1 x2 x3 x4 x5 x6 x7 b x5 0 7/2 0 0 3/2 1 1/2 -3/2 14 x3 1 5/2 0 1 1/2 0 1/2 1/2 13 x2 3 0 1 0 1 0 0 1 17 Z - C We can say, that: Select one: The solution is not optimal. The solution is optimal. The solution can be the initial solution.

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

100%

Suppose following simplex table:

		2	3	1	-1	0	0	-100
		x1	x2	x3	x4	x5	x6	x7	b
x5	0	7/2	0	0	3/2	1	1/2	-3/2	14
x3	1	5/2	0	1	1/2	0	1/2	1/2	13
x2	3	0	1	0	1	0	0	1	17
	Z - C

We can say, that:

Select one:

The solution is not optimal.

The solution is optimal.

The solution can be the initial solution.

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