23 X5 3 -3/4 20 -1/2 0 0 25 = 1/4* -8 -1 9 1 0 X6 = 1/2 -12 -1/2 3 0 1

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Q) While solving a standard form problem, we arrive at the following tableau. Continue the computation by using the Bland’s rule to find an optimal solution of the original problem.

 

 

23
X5
-3/4
20 -1/2
6 0 0
25 =
1/4*
-8
-1
9 1 0
X6 =
1/2
-12 -1/2
3 0 1
X7 =
1
1
0 0 0 1
3.
Transcribed Image Text:23 X5 -3/4 20 -1/2 6 0 0 25 = 1/4* -8 -1 9 1 0 X6 = 1/2 -12 -1/2 3 0 1 X7 = 1 1 0 0 0 1 3.
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