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Here is the optimal tableau for a standard Max problem. Z X1 X2 X3 X4 81 82 83 1 0 5 3 0 6 5 0 1 .3 7.5 0 -.1 .2 0 0 0 28 360 0 -8 12 1 60 0 -1/15 -3 1 1/15 -1/10 0 2 The original rhs was changed to 259 - rhs 2700 6 [300] 180 but the value of bi has been 300 First use the B-matrix method to find the new rhs for the above tableau (recall the shortcut for updated ž is y b where y is the dual solution and b is the updated rhs). what is the new value of b3 in the updated tableau? Complete using the Dual Simplex. what is the optimal value of z?

Here is the optimal tableau for a standard Max problem. Z X1 X2 X3 X4 81 82 83 1 0 5 3 0 6 5 0 1 .3 7.5 0 -.1 .2 0 0 0 28 360 0 -8 12 1 60 0 -1/15 -3 1 1/15 -1/10 0 2 The original rhs was changed to 259 - rhs 2700 6 [300] 180 but the value of bi has been 300 First use the B-matrix method to find the new rhs for the above tableau (recall the shortcut for updated ž is y b where y is the dual solution and b is the updated rhs). what is the new value of b3 in the updated tableau? Complete using the Dual Simplex. what is the optimal value of z?

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Here is the optimal tableau for a standard Max problem. X2 X3 X4 81 5 3 0 6 .3 7.5 0 -.1 28 360 0 -8 0 -1/15 -3 1 1/15 Z 1 0 1 0 0 0 X1 82 5 .2 12 -1/10 0 83 0 0 6 1 60 2 The following new constraint must be incorporated (i.e. Change 6): 50 x1 + 30 x2 + 15 x3 + 20 x4 ≥ 350 What is the new optimal value of z? rhs 2700 what is the value of the left side of this new constraint with the current optimal solution? To use Dual Simplex to get the new optimal solution, change this new constraint to a constraint and add a row (and an $4 column).
Transcribed Image Text:Here is the optimal tableau for a standard Max problem. X2 X3 X4 81 5 3 0 6 .3 7.5 0 -.1 28 360 0 -8 0 -1/15 -3 1 1/15 Z 1 0 1 0 0 0 X1 82 5 .2 12 -1/10 0 83 0 0 6 1 60 2 The following new constraint must be incorporated (i.e. Change 6): 50 x1 + 30 x2 + 15 x3 + 20 x4 ≥ 350 What is the new optimal value of z? rhs 2700 what is the value of the left side of this new constraint with the current optimal solution? To use Dual Simplex to get the new optimal solution, change this new constraint to a constraint and add a row (and an $4 column).
Here is the optimal tableau for a standard Max problem. Z 1 x1 0 1 0 0 0 X2 X3 X4 81 5 3 0 6 .3 7.5 0 -.1 28 360 0 -8 -1/15 -3 1 1/15 The original rhs was changed to 259 82 83 5 0 .2 0 12 1 -1/10 0 rhs 2700 6 60 2 [300] 180 but the value of bi has been 300 First use the B-matrix method to find the new rhs for the above tableau (recall the shortcut for updated ž is y b where y is the dual solution and b is the updated rhs). what is the new value of b3 in the updated tableau? Complete using the Dual Simplex. what is the optimal value of z?
Transcribed Image Text:Here is the optimal tableau for a standard Max problem. Z 1 x1 0 1 0 0 0 X2 X3 X4 81 5 3 0 6 .3 7.5 0 -.1 28 360 0 -8 -1/15 -3 1 1/15 The original rhs was changed to 259 82 83 5 0 .2 0 12 1 -1/10 0 rhs 2700 6 60 2 [300] 180 but the value of bi has been 300 First use the B-matrix method to find the new rhs for the above tableau (recall the shortcut for updated ž is y b where y is the dual solution and b is the updated rhs). what is the new value of b3 in the updated tableau? Complete using the Dual Simplex. what is the optimal value of z?
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