x = 0.99 1 1.01 y = 1.49 0.0300 0.0297 0.0294 y = 1.5| 0.0263 0.0260 0.0258 y = 1.51 0.0226 0.0224 0.0221 Notice if the two tables look nearly linear, and whether the second looks more linear than the particular, think about how you would decide if they were linear, or if the one were more clos linear than the other). (c) Give the local linearization of f(x, y) = e=² cos(y) at (1, 1.5): Using the second of your tables: f(x, y) = 0.0260-0.025(x-1)-0.365(y-1.5) Using the fact that fr(x, y) = -e cos(y) and fy(x, y) = -e sin(y): f(x, y) e^(1.5)sin(1)+e^(1.5)cos(1)(x-1)+e^(1.5)ln(e)sin(1)(y-1.5) %D
x = 0.99 1 1.01 y = 1.49 0.0300 0.0297 0.0294 y = 1.5| 0.0263 0.0260 0.0258 y = 1.51 0.0226 0.0224 0.0221 Notice if the two tables look nearly linear, and whether the second looks more linear than the particular, think about how you would decide if they were linear, or if the one were more clos linear than the other). (c) Give the local linearization of f(x, y) = e=² cos(y) at (1, 1.5): Using the second of your tables: f(x, y) = 0.0260-0.025(x-1)-0.365(y-1.5) Using the fact that fr(x, y) = -e cos(y) and fy(x, y) = -e sin(y): f(x, y) e^(1.5)sin(1)+e^(1.5)cos(1)(x-1)+e^(1.5)ln(e)sin(1)(y-1.5) %D
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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i need help with the last question in red
Transcribed Image Text:0.99
1
1.01
y = 1.49
0.0300
0.0297
0.0294
y = 1.5
0.0260
0.0263
0.0258
y = 1.51
0.0226
0.0224
0.0221
Notice if the two tables look nearly linear, and whether the second looks more linear than the first (in
particular, think about how you would decide if they were linear, or if the one were more closely
linear than the other).
(c) Give the local linearization of f(x, y)
Using the second of your tables:
= e- cos(y) at (1, 1.5):
f(x, y) - 0.0260-0.025(x-1)-0.365(y-1.5)
Using the fact that fa(x, y) = -e cos(y) and fy (x, y) = -e sin(y):
f(x, y) = e^(1.5)sin(1)+e^(1.5)cos(1)(x-1)+e^(1.5)ln(e)sin(1)(y-1.5)
6.
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