Suppose a random sample of 459 married couples found that 307 had two or more personality preferences in common. In another random sample of 471 married couples, it was found that only 31 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. Find a 95% confidence interval for p1-p2. Round your answer to three decimal places.

Suppose a random sample of 459 married couples found that 307 had two or more personality preferences in common. In another random sample of 471 married couples, it was found that only 31 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. Find a 95% confidence interval for p1-p2. Round your answer to three decimal places.

Name: Suppose a random sample of 459 married couples foundthat 307 had two
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: Suppose a random sample of 459 married couples foundthat 307 had two or more personality preferences incommon. In another random sample of 471 marriedcouples, it was found that only 31 had no preferences incommon. Let p1 be the population proportion

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A recent Gallup Poll interviewed a random sample of 1523 adults. Of these, 868 bought a lottery ticket in the past year. The same Gallup Poll asked its 1523 adult respondents and also 501 teens (ages 13 to 17) whether they generally approved of legal gambling: 63% of adults and 52% of teens said yes. The margin of error for a 95% confidence statement about teens would be a. greater than for adults, because the teen sample is smaller.b. less than for adults, because the teen sample is smaller.c. less than for adults, because there are fewer teens in the population.d. the same as for adults, because they both come from the same sample survey.e. Can't say, because it depends on what percent of each population was in the sample.
A random sample of 390 married couples found that 292 had two or more personality preferences in common. In another random sample of 582 married couples, it was found that only 36 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 95% confidence interval for p1 - P2. (Use 3 decimal places.) lower limit upper limit (b) Explain the meaning of the confidence interval in part (a) in the context of this problem. Does the confidence interval contain all positive, all negative, or both positive and negative numbers? What does this tell you (at the 95% confidence level) about the proportion of married couples with two or more personality preferences in common compared with the proportion of married couples sharing no personality preferences in common? O Because the interval contains…
Political polls typically sample randomly from the U.S. population to investigate the percentage of voters who favor some candidate or issue. The number of people polled is usually on the order of 1000. Suppose that one such poll asks voters how they feel about the President’s handling of environmental issues. The results show that 575 out of the 1280 people polled say they either approve or strongly approve of the President’s handling. a. Find a 95% confidence interval for the proportion of the entire voter population who approve or strongly approve of the President’s handling. b. If the same sample proportion were found in a sample twice as large—that is 1150 out of 2560—how would this affect the confidence interval? How would the confidence interval change if the confidence level were 90% instead of 95%?
A CBS News poll conducted July 29–August 4, 2014, surveyed 1344 randomly selected American adults. Of those surveyed, 726 say that their sympathies in the Middle East situation lie more with the Israelis than with the Palestinians. Give a 95% confidence interval for the proportion of all American adults whose sympathies in the Middle East situation lie more with the Israelis than with the Palestinians. (__Answer 1__, __Answer 2__) Give your answers to 3 decimal places.
A certain coffee packing company has three packing lines with the following production volumes of boxes per hour. You are an analyst and the manager entrusts you to carry out an analysis to establish whether or not there is a difference in the production of each line at 95% confidence.
A random sample of 372 married couples found that 292 had two or more personality preferences in common. In another random sample of 562 married couples, it was found that only 40 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 95% confidence interval for p1 – p2. (Use 3 decimal places.) lower limit =__ upper limit =__ (b) Explain the meaning of the confidence interval in part (a) in the context of this problem. Does the confidence interval contain all positive, all negative, or both positive and negative numbers? What does this tell you (at the 95% confidence level) about the proportion of married couples with two or more personality preferences in common compared with the proportion of married couples sharing no personality preferences in common? A-Because…
A random sample of 372 married couples found that 296 had two or more personality preferences in common. In another random sample of 574 married couples, it was found that only 20 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common. (a) Find a 90% confidence interval for p1 – p2. (Use 3 decimal places.)lower limit =upper limit=
CNN is conducting a poll, and wants to produce a 90% confidence interval for the proportion of all New York residents who favor legalizing recreational marijuana. Of the 602 randomly selected New Yorkers surveyed, 394 were in favor of the initiative. a. With 90% confidence, the proportion of New York residents who favor legalizing recreational marijuana is between BLANK and BLANK. b. Suppose that we survey 602 randomly selected Americans many times, and calculate a confidence interval for each group. About Blank . percent of these confidence intervals will contain the true population proportion of New Yorkers who favor legalizing recreational marijuana, and about BLANK percent will not contain the true population proportion.
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
In a survey of 40 students in an introductory statistics class, a professor asks how many states in the United States each student has visited. Using the data from the professor's sample, a 99% confidence interval for the average number of states all students at the professor's school have visited is found to be (6.78, 12.18). Determine whether each of the following statements is valid or invalid. You may assume that the sample is representative of all students at the professor's school. (a) We are 99% confident that the average number of states visited by the 40 students the professor surveyed is between 6.78 and 12.18. Valid Invalid (b) Based on the 99% confidence interval, there is evidence that the average number of states visited by all students at the professor's school is different from 16. Valid Invalid (c) We are 99% confident that the average number of states visited by all students at the professor's school is between 6.78 and 12.18. Valid Invalid (d)…
A random sample of 360 married couples found that 284 had two or more personality preferences in common. In another random sample of 568 married couples, it was found that only 36 had no preferences in common. Let p1 be the population proportion of all married couples who have two or more personality preferences in common. Let p2 be the population proportion of all married couples who have no personality preferences in common.(a) Find a 90% confidence interval for p1 – p2. (Use 3 decimal places.)lower limit =upper limit = (b) Explain the meaning of the confidence interval in part (a) in the context of this problem. Does the confidence interval contain all positive, all negative, or both positive and negative numbers? What does this tell you (at the 90% confidence level) about the proportion of married couples with two or more personality preferences in common compared with the proportion of married couples sharing no personality preferences in common? Choose one: -We can not make any…
The dean of students at a large college is interested in learning about their opinions regarding the percentage of first-year students who should be given parking privileges in the main lot. He sends out an email survey to all students about this issue. A large number of first-year students reply but very few sophomores, juniors, and seniors reply. Based on the responses he receives, he constructs a 90% confidence interval for the true proportion of students who believe first-year students should be given parking privileges in the main lot to be (0.71, 0.79). Which of the following may have an impact on the confidence interval, but is not accounted for by the margin of error? response bias O nonresponse bias O sampling variation O undercoverage bias