Q1Suppose a drug company designs to develop a new drug to prevent colds. The companystates that the drug is equally effective for men and women. To test this claim, theychoose a simple random sample of 100 women and 200 men from a population of100,000 volunteers.At the end of the study, 38 women caught a cold; and 102 men caught a cold.(a) Based on these findings, can we reject the company's claim that the drug is equallyeffective for men and women? Use a 0.05 level of significance.(b) Find the 95% confidence interval for the difference between the proportions ofwomen and men caught a cold.(c) Are the results of (a) and (b) consistent? Explain briefly.

There are two independent samples which are women and men. We have to test whether the drug is…

Answered: Suppose a drug company designs to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A local school board wants to estimate the difference in the proportion of households with school-aged children that would support starting the school year a week earlier, and the proportion of households without school-aged children that would support starting the school year a week earlier. They survey a random sample of 40 households with school-aged children about whether they would support starting the school year a week earlier, and 38 households respond yes. They survey a random sample of 45 households that do not have school-aged children, and 25 respond yes. The school board plans to construct a 90% confidence interval for the difference in proportions of households who would support starting the school year a week earlier. Are the conditions for inference met? A) Yes, the conditions for inference are met. B) No, the 10% condition is not met. C) No, the randomness condition is not met. D) No, the Large Counts Condition is not met.
A report described a survey of parents of children under the age of 18. Each person in a representative sample of 838 working fathers and a sample of 595 working mothers was asked if balancing the responsibilities of a job and a family was difficult. It was reported that 437 of the fathers surveyed and 364 of the mothers surveyed said that it was difficult. The two samples were independently selected and were thought to be representative of working fathers and mothers of children under 18 years old. USE SALT Use this information to calculate a 95% confidence interval estimate of the difference between the proportion of working fathers who find balancing work and family difficult, p₁, and this proportion for working mothers, P2. (Use a statistical computer package to calculate the P-value. Use P₁ - P₂. Round your answers to three decimal places.) to Interpret the interval. O There is a 95% chance that the true difference between the proportion of working fathers who find balancing work…
A survey of 1000 adults from a certain region asked, "If purchasing a used car made certain upgrades or features more affordable, what would be your preferred luxury upgrade?" The results indicated that 58% of the females and 51% of the males answered window tinting. The sample sizes of males and females were not provided. Suppose that of 600 females, 348 reported window tinting as their preferred luxury upgrade of choice, while of 400 males, 204 reported window tinting as their preferred luxury upgrade of choice. Complete parts (a) through (d) below. a. Is there evidence of a difference between males and females in the proportion who said they prefer window tinting as a luxury upgrade at the 0.05 level of significance? State the null and alternative hypotheses, where π1 is the population proportion of females who said they prefer window tinting as a luxury upgrade and π2 is the population proportion of males who said they prefer window tinting as a luxury…
A psychologist wants to know whether viewing more violent TV shows affects aggressive behavior. 12 children were chosen at random for an experiment and randomly allocated to one of two conditions. In condition 1, six kids were given an aggressive behavior test. The more aggressive the conduct, the higher the score. In condition 2, six children were given the identical test after watching two hours of tv shows. The following results were obtained. Condition 1 5 14 6 8 7 6 Condition 2 12 14 14 8 15 9 Assume the obtained value of the appropriate statistic is t obt = -2.431, using α = 0.05, 2 tail, and t crit = +2.228 and -2.228, what do you conclude? a. retain null hypothesis, suggesting that violent TV show does not affect aggression. b. reject null hypothesis, suggesting that violent TV show affects aggression.
In randomized, double-blind clinical trials of a new vaccine, children were randomly divided into two groups. Subjects in group 1 received the new vaccine while subjects in group 2 received a control vaccine. After the second dose, 125 of 746 subjects in the experimental group (group 1) experienced fever as a side effect. After the second dose, 82 of 627 of the subjects in the control group (group 2) experienced fever as a side effect. Does the evidence suggest that a higher proportion of subjects in group 1 experienced fever as a side effect than subjects in group 2 at the a= 0.01 level of significance? Find the test statistic for this hypothesis test. (Round to two decimal places as needed.)
An anger-management course claims that, after completing its seminar, participants will lose their tempers less often. Always a skeptic, you decide to test this claim. A random sample of 12 seminar participants is chosen, and these participants are asked to record the number of times that they lost their tempers in the two weeks prior to the course. After the course is over, the same participants are asked to record the number of times that they lost their tempers in the next two weeks. The following table lists the results of the survey. Using these data, test the claim at the 0.01 level of significance assuming that the population distribution of the paired differences is approximately normal. Let participants before completing the anger-management course be Population 1 and let participants after completing the anger-management course be Population 2. Number of Times Temper Was Lost during a Two-Week Period Before 10 6 8 10 6 3 10 3 8 After 6 7 4 4 8 6 4 9 3 7 Copy Data Step 2 of 3:…
You take 115 random samples from a population of trees for which the mean height in feet is μ=72μ=72 (but you do not know this), and use each set of data to do a hypothesis test at a 5% level of significance to determine if the population mean is not 72. So the hypotheses are:Ho:μ=72Ho:μ=72Ha:μ≠72Ha:μ≠72In how many of the 115 hypothesis tests would you expect to reject Ho and conclude that the population mean is not 72? Do not round your answer.
A psychologist wants to know whether viewing more violent TV shows affects aggressive behavior. 12 children were chosen at random for an experiment and randomly allocated to one of two conditions. In condition 1, six kids were given an aggressive behavior test. The more aggressive the conduct, the higher the score. In condition 2, six children were given the identical test after watching two hours of tv shows. The following results were obtained. Condition 1 5 14 6 8 7 6 Condition 2 12 14 14 8 15 9 Q1, The alternative (H1) hypothesis and null (H0) hypothesis are (2-tail) _________. a. H1: violent TV show does not affects aggressive behavior H0: violent TV show affects aggressive behavior b. H1: violent TV show affects aggressive behavior H0: violent TV show does not affect aggressive behavior
Provide an appropriate response. A medical researcher wishes to try three different techniques to lower cholesterol levels of patients with high cholesterol levels. The subjects are randomly selected and assigned to one of three groups. Group 1 is given medication, Group 2 is given an exercise program, and Group 3 is assigned a diet program. At the end of six weeks, each subject's cholesterol level is recorded. Test the hypothesis that there is no difference among the means. Use a = 0.05. Apply p-value approach. Round p-value to nearest thousandth. Show step1-step3. Group1 Group2 Group3 11 8 8 12 3 12 13 10 4 15 6 6 9. 9.
A cat-lover claims that cats are just as smart as dogs. In order to back this claim up with some evidence she organizes a study at a large local pet daycare center. A random sample of 40 cats are selected and a random sample of 40 dogs are selected. Each of the selected animals is given one hour with a trainer in which the trainer attempts to teach them to roll over. Upon conclusion of the training, the proportion of dogs and proportion of cats that have learned this skill is computed. The trainer reports that she is 90% confident that the true difference in the proportion of all dogs and all cats (pD – pC) that can learn this skill with one hour of training is between –0.05 to 0.28. Which of the following conclusions can be made based upon this confidence interval? (A) Because most of the values in the confidence interval are positive, this proves that dogs are smarter than cats. (B) Because the point estimate of the confidence interval is positive, there is convincing evidence…
A local school board wants to estimate the difference in the proportion of households with school-aged children that would support starting the school year a week earlier, and the proportion of households without school-aged children that would support starting the school year a week earlier. They survey a random sample of 40 households with school-aged children about whether they would support starting the school year a week earlier, and 30 households respond yes. They survey a random sample of 45 households that do not have school-aged children, and 25 respond yes. Assuming the conditions for inference have been met, what is the 90% confidence interval for the difference in proportions of households that would support starting the school year a week earlier? Find the z-table here. 0.75(1-0.75), 0.56(1-0.56) O (0.75 - 0.56) ±1.65 45 40 0.75(1-0.75) 0.56(1-0.56) O (0.75 - 0.56) ±1.96, 85 85 O (0.75 - 0.56) ±1.65, 0.75(1-0.75) 0.56(1-0.56) + 40 45 O (0.75 - 0.56) ±1.96 0.75(1-0.75)…
A local school board believes there is a difference in the proportion of households with school-aged children that would support starting the school year a week earlier, and the proportion of households without school- aged children that would support starting the school year a week earlier. They survey a random sample of 40 households with school-aged children about whether they would support starting the school year a week earlier, and 38 households respond yes. They survey a random sample of 45 households that do not have school-aged children, and 25 respond yes. Let p3= the true proportion of households with school-aged children that would support starting the school year a week early and pw= the true proportion of households without school-aged children that would support starting the school year a week earlier. The P-value for this significance test is 0.000034. Which of the following is the correct conclusion for this test of the hypotheses Ho: P;- Pw=0 and H, P,- Pw0 at the a =…

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