A large fishing farm with thousands of fish has been treating its fish to stop a spreading fungalinfection. A simple random sample of 150 fish is taken and a careful examination determines that 12 ofthe fish sampled are infected. The infection would be contained if fewer than 10% of the fish wereinfected. What is the conclusion in the context of the problem?There is enough evidence to support Ha.O There is not enough evidence to suggest that the infection would be contained.O There is statistical evidence to suggest that the infection would be contained.O There is enough evidence to accept the null hypothesis.

From the given information, A simple random sample of 150 fish is taken and a careful examination determines that 12 of the fist sampled are infected. The infection would be contained if fewer than 10% of the fish were infected. Null Hypothesis: H0: p>=0.10 Alternative Hypothesis: H1: p<0.10 Sample proportion, p^=x/n=12/150=0.08 Test statistic: z=p^-pp(1-p)n =0.08-0.100.101-0.10150 =-0.8165 p value: P=P(z<test statistic) =Pz<-0.8165 =0.2071 Decision Rule: If p-value ≤ α, then reject the null hypothesis. Conclusion: The level of significance is α=0.05 Here, the p-value is greater than the level of significance. From the decision rule, failed to reject the null hypothesis.