In a 2013 poll, it was found that 0.78 of Americans cover their mouth when sneezing. A sociologist claimsthat this proportion has decreased since then. She wishes to test the following claim (H1) at a significancelevel of a=0.10.Ho p=0.78H₁: p<0.78She obtains a random sample of 21 Americans and finds that 13 cover their mouth when sneezing.The p-value for this test is the probability of observing...O at most 13 Americans cover their mouth when sneezing.O at least 13 Americans cover their mouth when sneezing.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value=The p-value is...O less than (or equal to) agreater than aThis test statistic leads to a decision to...O reject the nullO accept the nullO fail to reject the nullоescW4925%eSPว As such, the final conclusion is that...O There is sufficient evidence to warrant rejection of the claim that the population proportion ofAmericans who cover their mouth when sneezing is less than 0.78.O There is not sufficient evidence to warrant rejection of the claim that the population proportion ofAmericans who cover their mouth when sneezing is less than 0.78.O The sample data support the claim that the population proportion of Americans who cover theirmouth when sneezing is less than 0.78.O There is not sufficient sample evidence to support the claim that the population proportion ofAmericans who cover their mouth when sneezing is less than 0.78.Submit Questionоesc2#3M6425

The question is about hypothesis testing.Given :Population proportion of people from country "A"…

Answered: In a 2013 poll, it was found that 0.78…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose a study reported that the average persin watched 3.37 hours of television per day. a random sample of 15 people gave the number of hours of television watched per day shown below. at the 1% significance level, do the data provide sufficent evidence to conclude that the amount of television watched per day last year by the average person is greater than the value reported in the study? what is the test statistic value for this problem? a.0.28 b.-38 c.none of the above d. 0.58 e.-4.295 f..04 g. 1.94 . the proper conclusion for this problem is? a. reject the null hypothesis we have sufficent evidence to prove the average number of hours people watch tv is more than 3.37 hours. b. Do not reject the null hypothesis we have sufficient evidence to prove the average number of hours of TV watched is greater than 3.37 hours c. Reject the null hypothesis and claim the average number of hours people watch TV is less than 3.37 because the P value is near zero d. Do not reject the null…
A dietician wishes to see if a person’s cholesterol level will change if the diet is supplemented by a certain mineral. Six randomly selected subjects were pretested, and then they took the mineral supplement of a 6 week period. The results are shown in the table below. Can it be concluded that the cholesterol level has changed at a significance level of 0.10? Use the P-value method with your calculator. Assume the variable is approximately normally distributed. You can use your calculator to answer this question but make sure that you clearly write the statements for the null and alternative hypothesis. Be sure that you thoroughly explain your final conclusion using the P-value method. Subject 1 2 3 4 5 6 Before 210 235 208 190 172 244 After 190 170 210 188 173 228
In a random sample of 925 plain M&M's, 19% were blue. Use a 0.01 significance level to test the claim of Mars, Inc. that 24% of its plain M&M candies are blue. a. Define the parameter A. p = The proportion of all M&M's that are blue B. mu = The proportion of all M&M's that are blue C. mu = The mean number of all M&M's that are blue D. p = The proportion of all M&M's that are not blue b. State the null and alternative hypotheses A. Upper H 0 : p greater than 0.24 Upper H 1 : p equals 0.24 B. Upper H 0 : p equals 0.19 Upper H 1 : p not equals 0.19 C. Upper H 0 : p equals 0.24 Upper H 1 : p not equals 0.24 D. Upper H 0 : mu not equals 0.24 Upper H 1 : mu equals 0.24 c. Calculate the test statistic. Which of these options is closest to the test statistic? A. negative 4.00 B. negative 3.65 C.…
Is the proportion of wildfires caused by humans in the south different from the proportion of wildfires caused by humans in the west? 350 of the 519 randomly selected wildfires looked at in the south were caused by humans while 383 of the 500 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? Rectangular Snip a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: Select an answer | (please enter a decimal) Select an answer v Select an answer H1: Select an answer v Select an answer vSelect an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.)
A poll was conducted to investigate opinions about global warming. The respondents who answered yes when asked if Question Viewer idence that the earth is getting warmer were then asked to select a cause of global warming. The results are given in the accompanying data table. Use a 0.05 significance level to test the claim that the sex of the respondent is independent of the choice for the cause of global warming. Do men and women appear to agree, or is there a substantial difference? Human activity Natural patterns Male 340 164 Female 319 161 Click here to view the chi-square distribution table. Identify the null and alternative hypotheses. The sex of the respondent The sex of the respondent Ho: H₁: Compute the test statistic. Don't know 27 29 and the choice for the cause of global warming are independent. and the choice for the cause of global warming are dependent. (Round to three decimal places as needed.)
You wish to test the following daim (Ha) at a significance level of a = 0.001. H.:P1 2 P2 Ha:P1 < P2 You obtain a sample from the first population with 244 successes and 117 failures. You obtain a sample from the second population with 523 successes and 202 failures. test statistic = [three decimal accuracy] p-value = [four decimal accuracy) The p-value is... O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null hypothesis O fail to reject the null hypothesis As such, the final condusion is that... O There is sufficient evidence to support that the first population proportion is less than the second population proportion. There is not sufficient evidence to support that the first population proportion is less than the second population proportion.
The coach of a very popular men’s basketball team claims that the average distance the fans travel to the campus to watch a game is 35 miles. The team members feel otherwise. A sample of 16 fans who travel to games was randomly selected and yielded a mean of M= 36 miles and s= 5 miles. Test the coach’s claim at the 5% (.05) level of significance. one-tailed or two-tailed test: State the hypotheses: df= tα or t value for the critical region = sM = t (test statistic)= Decision:
The mean potassium content of a popular sports drink is listed as 132 mg in a 32-oz bottle. Analysis of 24 bottles indicates a sample mean of 131.2 mg. (a) State the hypotheses for a two-tailed test of the claimed potassium content.. a. Ho: μ= 132 mg vs. H₁: b. He: ≤132 mg vs. H₁: c. He: ≥132 mg vs. H₁: Oa Ob Oc (b) Assuming a known standard deviation of 2.1 mg, calculate the z test statistic to test the manufacturer's claim. (Round your answer to 2 decimal places. A negative value should be indicated by a minus sign.) Test statistic 132 mg >132 mg <132 mg (c) At the 2 percent level of significance (a = .02) does the sample contradict the manufacturer's claim? Decision Rule: Reject Ho
Listed below are the number of cricket chirps in 1 min and the corresponding temperatures in degrees Fahrenheit. Is there sufficient evidence to conclude that there is a relationship between the number of cricket chirps in 1 min and the temperature? Use a significance level of α=0.05. Chirps in 1 min 1171 1105 1185 852 1089 950 917 862 Temperature (°F) 78.4 88.2 91.5 86.3 90.2 79.3 83.8 84.4 Determine the null and alternative hypotheses for this test. Find the value of the correlation coefficient. rs=enter your response here (Round to three decimal places as needed.) Determine the critical value(s) of the correlation coefficient. enter your response here (Round to three decimal places as needed. Use a comma to separate answers as needed.)
A health insurance company wants to determine if more than 25% of US residents have been to a hospital emergency room within the past year. It was found that in a sample of 1000 people, 28% indicated that they had been to an emergency room within the past year. With a significance level of 0.01, is there evidence to suggest that the proportion of US residents that have been to the emergency room in the past year is actually higher than 25%?
In one study of smokers who tried to quit smoking with nicotine path therapy,38 were smoking one year after the treatment, and 32 were not smoking one year after the treatment. Use a 0.10 significance level to test the claim that among smokers who try to quit with nicotine patch therapy, the majority are smoking a year after the treatment. d. Calculate the test statistic z. Which of these options is closest to z? A. negative 2.02 B. 0.72 C. negative 0.25 D. 2.59 e. Calculate the P-value. Which of these options is closest to the P-value? A. 0.2358 B. 0.2164 C. 0.3359 D. 0.2271 f. State the technical conclusion A. Reject Upper H 0 B. Do not reject Upper H 0 g. State the final conclusion A. There is sufficient evidence to warrant rejection of the claim. B. There is not sufficient evidence to warrant rejection of the claim.…

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