Suppose a 500. mL flask is filled with 0.80 mol of Br₂, 1.2 mol of OC1₂ and 1.7 mol of BrOCI. The following reaction becomes possible: Br₂(g) + OC1₂(g) → BrOC1 (g) + BrC1 (g) The equilibrium constant K for this reaction is 1.75 at the temperature of the flask. Calculate the equilibrium molarity of BrOC1. Round your answer to two decimal places. M X ?

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### Chemistry Equilibrium Calculation

#### Problem Statement

Suppose a 500. mL flask is filled with 0.80 mol of Br\(_2\), 1.2 mol of OCl\(_2\), and 1.7 mol of BrOCl. The following reaction becomes possible:

\[ \text{Br}_2 (g) + \text{OCl}_2 (g) \rightleftharpoons \text{BrOCl} (g) + \text{BrCl} (g) \]

The equilibrium constant \(K\) for this reaction is 1.75 at the temperature of the flask.

Calculate the equilibrium molarity of BrOCl. Round your answer to two decimal places.

#### Instructions for Calculation

1. **Initial Concentrations**:
   - Determine the initial concentrations of the reactants and products by dividing the number of moles by the volume of the flask.
   - Flask Volume = 500 mL = 0.500 L
   
   For Br\(_2\):
   \[ [Br_2]_0 = \frac{0.80 \text{ mol}}{0.500 \text{ L}} = 1.60 \text{ M} \]

   For OCl\(_2\):
   \[ [OCl_2]_0 = \frac{1.2 \text{ mol}}{0.500 \text{ L}} = 2.40 \text{ M} \]

   For BrOCl:
   \[ [BrOCl]_0 = \frac{1.7 \text{ mol}}{0.500 \text{ L}} = 3.40 \text{ M} \]

2. **Reaction Table**:
   - Set up an ICE (Initial, Change, Equilibrium) table to determine the changes in concentration as the system achieves equilibrium.

3. **Equilibrium Expression**:
   - Use the equilibrium constant expression for the balanced equation.
   \[ K = \frac{[BrOCl][BrCl]}{[Br_2][OCl_2]} \]

4. **Solving for \(x\)**:
   - Introduce the changes in concentration (\(-x\) for reactants and \(+x\) for products).
   - Apply the equilibrium constant \(K\) to find the value of \(x\).

5. **Calculate
Transcribed Image Text:### Chemistry Equilibrium Calculation #### Problem Statement Suppose a 500. mL flask is filled with 0.80 mol of Br\(_2\), 1.2 mol of OCl\(_2\), and 1.7 mol of BrOCl. The following reaction becomes possible: \[ \text{Br}_2 (g) + \text{OCl}_2 (g) \rightleftharpoons \text{BrOCl} (g) + \text{BrCl} (g) \] The equilibrium constant \(K\) for this reaction is 1.75 at the temperature of the flask. Calculate the equilibrium molarity of BrOCl. Round your answer to two decimal places. #### Instructions for Calculation 1. **Initial Concentrations**: - Determine the initial concentrations of the reactants and products by dividing the number of moles by the volume of the flask. - Flask Volume = 500 mL = 0.500 L For Br\(_2\): \[ [Br_2]_0 = \frac{0.80 \text{ mol}}{0.500 \text{ L}} = 1.60 \text{ M} \] For OCl\(_2\): \[ [OCl_2]_0 = \frac{1.2 \text{ mol}}{0.500 \text{ L}} = 2.40 \text{ M} \] For BrOCl: \[ [BrOCl]_0 = \frac{1.7 \text{ mol}}{0.500 \text{ L}} = 3.40 \text{ M} \] 2. **Reaction Table**: - Set up an ICE (Initial, Change, Equilibrium) table to determine the changes in concentration as the system achieves equilibrium. 3. **Equilibrium Expression**: - Use the equilibrium constant expression for the balanced equation. \[ K = \frac{[BrOCl][BrCl]}{[Br_2][OCl_2]} \] 4. **Solving for \(x\)**: - Introduce the changes in concentration (\(-x\) for reactants and \(+x\) for products). - Apply the equilibrium constant \(K\) to find the value of \(x\). 5. **Calculate
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