Phosphorous pentachloride decomposes according to the reaction PCI, (g) = PCI, (g) + Cl, (g) A 14.7 g sample of PCl, is added to a sealed 1.25 L flask and the reaction is allowed to come to equilibrium at a constant temperature. At equilibrium, 33.2% of the PCI, remains. What is the equilibrium constant, Ke, for the reaction?
Phosphorous pentachloride decomposes according to the reaction PCI, (g) = PCI, (g) + Cl, (g) A 14.7 g sample of PCl, is added to a sealed 1.25 L flask and the reaction is allowed to come to equilibrium at a constant temperature. At equilibrium, 33.2% of the PCI, remains. What is the equilibrium constant, Ke, for the reaction?
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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
Transcribed Image Text:Phosphorous pentachloride decomposes according to the reaction
PCI, (g) = PCI, (g) + Cl, (g)
A 14.7 g sample of PCl, is added to a sealed 1.25 L flask and the reaction is allowed to come to equilibrium at a constant
temperature. At equilibrium, 33.2% of the PCl, remains. What is the equilibrium constant, Ke, for the reaction?
Expert Solution
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Step 1
mass of PCl5 = 14.7 gm
molar mass of PCl5 = 208.24 gm/mol
moles of PCl5 = (14.7 gm / 208.24 gm/mol) = 0.0706 mol
Given that,
volume of the flask = 1.25 L
concentration of PCl5 = (0.0706 mol / 1.25 L) = 0.0565 M
At equilibrium 33.2% of PCl5 remains
so, at equilibrium [PCl5] = (33.2/100) x 0.0565 = 0.0187 M
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