Suppose 26 mol of methanol and 12 mol of oxygen combine in the following combustion reaction: 2CH3OH(1)+302(g) → 2CO2(g) + 4H₂O(g) What is the excess reactant and how many moles of it remains at the end of the reaction? O 14 mol CH3OH(1) O 8 mol CH3OH(1) 8 mol CO₂ (g) O5 mol O₂(g) 18 mol CH3OH(1) Submit Request Answer

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Suppose 26 mol of methanol and 12 mol of oxygen combine in the following combustion reaction:
2CH3OH(1)+302(g) → 2CO2(g) + 4H₂O(g)
What is the excess reactant and how many moles of it remains at the end of the reaction?
O 14 mol CH3OH(1)
O 8 mol CH3OH(1)
O 8 mol CO2 (g)
O 5 mol O2(g)
O 18 mol CH3OH (1)
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Transcribed Image Text:Suppose 26 mol of methanol and 12 mol of oxygen combine in the following combustion reaction: 2CH3OH(1)+302(g) → 2CO2(g) + 4H₂O(g) What is the excess reactant and how many moles of it remains at the end of the reaction? O 14 mol CH3OH(1) O 8 mol CH3OH(1) O 8 mol CO2 (g) O 5 mol O2(g) O 18 mol CH3OH (1) Submit Request Answer
Molten gallium reacts with arsenic to form the semiconductor gallium arsenide, GaAs, used in light-emitting diodes and solar cells:
Ga(1) + As(s) → GaAs(s)
If 3.00 g of gallium is reacted with 4.90 g of arsenic, how many grams of the excess reactant are left at the end of the reaction?
O 1.68 g As
O 3.22 g As
O 6.22 g Ga
O 1.90 g As
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Transcribed Image Text:Molten gallium reacts with arsenic to form the semiconductor gallium arsenide, GaAs, used in light-emitting diodes and solar cells: Ga(1) + As(s) → GaAs(s) If 3.00 g of gallium is reacted with 4.90 g of arsenic, how many grams of the excess reactant are left at the end of the reaction? O 1.68 g As O 3.22 g As O 6.22 g Ga O 1.90 g As Submit Request Answer
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