For the following reaction, 0.459 moles of methane (CH4) are mixed with 0.320 moles of carbon tetrachloride. methane (CH4)(g)+carbon tetrachloride(g) > dichloromethane (CH2Cl2)(g)   What is the formula for the limiting reagent? What is the maximum amount of dichloromethane (CH2Cl2) that can be produced?

Chemistry for Engineering Students
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Chapter3: Molecules, Moles, And Chemical Equations
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Problem 3.75PAE: 3.75 The following pictures show a molecular-scale view of a chemical reaction between the compounds...
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For the following reaction, 0.459 moles of methane (CH4) are mixed with 0.320 moles of carbon tetrachloride.

methane (CH4)(g)+carbon tetrachloride(g) > dichloromethane (CH2Cl2)(g)
 

What is the formula for the limiting reagent?

What is the maximum amount of dichloromethane (CH2Cl2) that can be produced?

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