Bonus 1: CH4(g) ± C12(g) → CH2C12(g) + HCI(g) Methane gas reacts with chlorine gas to form dichloromethane and hydrogen chloride, as represented by the equation above. (a) A 25.0 g sample of methane gas is placed in a reaction vessel containing 2.58 mol of C12 (g). ) Identify the limiting reactant when the methane and chlorine gases are combined. Justify your answer with a calculation. (ii) Calculate the total number of moles of CH2C12(g) in the container after the limiting reactant has been totally consumed.

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Chapter1: Chemical Foundations
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Balance the chemical reaction, and complete the stoichiometry problem attached. 

 

CH4(g) + C12 (g) → CH2C12(g) + HCl(g)
Bonus 1:
Methane gas reacts with chlorine gas to form dichloromethane and hydrogen chloride, as
represented by the equation above.
(a) A 25.0 g sample of methane gas is placed in a reaction vessel containing 2.58 mol of C12(g).
() Identify the limiting reactant when the methane and chlorine gases are combined. Justify your
answer with a calculation.
(ii) Calculate the total number of moles of CH2C12 (g) in the container after the limiting reactant
has been totally consumed.
Transcribed Image Text:CH4(g) + C12 (g) → CH2C12(g) + HCl(g) Bonus 1: Methane gas reacts with chlorine gas to form dichloromethane and hydrogen chloride, as represented by the equation above. (a) A 25.0 g sample of methane gas is placed in a reaction vessel containing 2.58 mol of C12(g). () Identify the limiting reactant when the methane and chlorine gases are combined. Justify your answer with a calculation. (ii) Calculate the total number of moles of CH2C12 (g) in the container after the limiting reactant has been totally consumed.
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