Summarize and write IN YOUR OWN WORDS: Gas forming reactions:1. To a dry 10×75 or 13x100 mm test tube, add a small piece of solid CaCO3. Add ~3 mL ofdeionized water followed by ~2 mL of 2 M HCl using a graduated cylinder. Record yourobservations.2. Repeat step 1 using scoop of solid NazSO4 that is about the size of a match head in place ofCACO3.3. Add a small scoop of NH4C1 solid about the size of a match head to a 10×75 or 13×100 mm testtube with 2 mL of deionized water, note the odor. Then add ~2 mL of 1 M NaOH, record yourobservations and again note the odor.Rinse your test tubes into a waste beaker using your wash bottle and dispose of the waste as per yourinstructor's directions.Neutralization Reactions:1. Add a match head size scoop of of Mg(OH)2 into a 10×75 or 13x100 mm test tube. Using agraduated cylinder to measure, ad ~3 mL of deionized water to the test tube then swirl themixture.2. Using a graduated cylinder to measure, add - 5 mL of 1.0 M HCl to the Mg(OH)2/deionizedwater test tube and swirl. Observe what happens, upon mixing.3. Add - 2 mL of 2.0 M HCl to - 2 mL of 1.0 M NaOH in a 15x150 mm test tube. What happensto the temp of the test tube?Rinse your test tubes into a waste beaker using your wash bottle and dispose of the waste as per yourinstructor's directions.

Gas forming reactions: In a dry test tube (10x75 or 13x100mm) take a small piece of solid CaCO3, add…

Answered: Summarize and write IN YOUR OWN WORDS:

Science

Chemistry

Summarize and write IN YOUR OWN WORDS:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

L Moving to another question will save this response. Question 18 Which is not an important property of water? a. Solvency b. Adhesion c. Cohesion d. All of the above are important A Moving to another question will save this response. 15,213 FEB 25 Question 18 of 40> 2.5 points Question 18 of 40 tv Save Answer C A ssa
Why are the formulas that I chose.... wrong?
10. Molecules that interact with the infrared region of the electromagnetic spectrum, use the energy of the infrared radiation to: a. vibrate b. rotate (spin) c. break bonds apart
Your roommate, a history student, has stumbled across nitrogen trifluoride in their history textbook because it was used in the 1960s and 1970s as rocket fuel oxidizer. They remember learning about chemical reactions in Grade 11 and want to make nitrogen trifluoride using nitrogen gas and fluorine gas. Since you are a chemistry student, you have decided to help them remember how to construct the formula. Your other roommate, who is a mathematics student, wants to create a hypothetical situation so that the history student can better understand the concept. She writes down a mass for fluorine gas and nitrogen gas. 1. If she wrote that the mass of nitrogen gas as 114.6 g and the mass of fluorine gas as 354.8 g which is the limiting reagent in this case? 2. The mass of nitrogen trifluoride produced that she wrote is 469.4 g. What is the theoretical mass of nitrogen trifluoride produced calculated using the given masses? Is this higher or lower than the mass that she wrote? 3. If it is…
help please answer in text form with proper workings and explanation for each and every part and steps with concept and introduction no AI no copy paste remember answer must be in proper format with all working
d.The simplifying assumption that the change in concentration of the reactants is SMALL (and therefore negligible to the calculation) compared to the initial concentration of the reactants. Is this assumption justified in this reaction and these conditions? Do a little math to prove your point.
Given the following thermochemical equations: C +;02 → CÓ 99 k.J ΔΗ- тol 294.5 kJ CO + 02 → CO2 ΔΗ= mol Calculate the enthalpy change for the reaction below: C+ O2 → CO2 → CO2 195.5 kJ/mol O -195.5 kJ/mol O -393.5 kJ/mol O -96.5 kJ/mol