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*subject: civil engineering - Reinforced prestressed concrete *please refer attached picture formula A square tied column to support an axial dead load of 529 kN and axial live load of 663 kN. fc'=25.72 MPa, fy = 332 MPa, gross P= 0.028. The no. of 23mm bars to be used is ___pieces. round off zero decimal places

*subject: civil engineering - Reinforced prestressed concrete *please refer attached picture formula A square tied column to support an axial dead load of 529 kN and axial live load of 663 kN. fc'=25.72 MPa, fy = 332 MPa, gross P= 0.028. The no. of 23mm bars to be used is ___pieces. round off zero decimal places

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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*subject: civil engineering - Reinforced prestressed concrete

*please refer attached picture formula


A square tied column to support an axial dead load
of 529 kN and axial live load of 663 kN. fc'=25.72
MPa, fy = 332 MPa, gross P= 0.028. The no. of 23mm
bars to be used is ___pieces.


round off zero decimal places 

 

Please refer this Formula Design of axially Loaded Tied Columns Given :axial load, fc', fy Required: Column size, size of main bars, size and spacing of lateral ties General Procedure 1.Solve for design axial load Pu 2.Assume pg 0.01 to 0.08 3. Solve for required gross area to get column size Ag = P₁₁ (0.65 )0.8 0.85 fc' (1- pg) + Pgfy. 4. Solve for Ast Ast = PAg 5. Using adjusted values of column size and Astr check column capacity (optional) P₁ = 0.80{0.85fc'(Ag-Ast) + Astfy} 6. Assume size ot ties and solve for the spacing Use the smallest value from the ff: a) 16 times longitudinal bar diameter b) 48 times tie diameter c) least dimension of the column
Transcribed Image Text:Please refer this Formula Design of axially Loaded Tied Columns Given :axial load, fc', fy Required: Column size, size of main bars, size and spacing of lateral ties General Procedure 1.Solve for design axial load Pu 2.Assume pg 0.01 to 0.08 3. Solve for required gross area to get column size Ag = P₁₁ (0.65 )0.8 0.85 fc' (1- pg) + Pgfy. 4. Solve for Ast Ast = PAg 5. Using adjusted values of column size and Astr check column capacity (optional) P₁ = 0.80{0.85fc'(Ag-Ast) + Astfy} 6. Assume size ot ties and solve for the spacing Use the smallest value from the ff: a) 16 times longitudinal bar diameter b) 48 times tie diameter c) least dimension of the column
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