Seatwork No. 1 1 whole yellow sheet of paper or bond paper A rectangular beam having a 7-m simple span is to Support a superimposed dead load of 28 kN/m and a live lood of x. The unit weight of concrete is 24 kN/m² Consider only 1 layer of reinforcements at the tension zone Ase Pmax to compute your area of steel. Given fé-40 MPa f₂ 400 MPa X= ID. No. 1000 ≤x≤ 2000 424 - 1000 = (424 N/m 1,950 N/m 3950 - 2000 =

Seatwork No. 1 1 whole yellow sheet of paper or bond paper A rectangular beam having a 7-m simple span is to Support a superimposed dead load of 28 kN/m and a live lood of x. The unit weight of concrete is 24 kN/m² Consider only 1 layer of reinforcements at the tension zone Ase Pmax to compute your area of steel. Given fé-40 MPa f₂ 400 MPa X= ID. No. 1000 ≤x≤ 2000 424 - 1000 = (424 N/m 1,950 N/m 3950 - 2000 =

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question

Seatwork No. 11 whole yellow sheet of paper or bondpaper
A rectangular beam having a 7-m simple span is to
Support a superimposed dead load of 28 kN/m and a
live lood of x. The unit weight of concrete is 24 kN/m²
Consider only 1 layer of reinforcements at the tension Zone.
Ise Pmax to compute your area of steel.
Given
fc-40 MPa
fg 400 MPa
X= ID. No.
1000≤x≤ 2000
424 - 1000 = 1424 N/m
3950 - 2000 = 1,950 N/m

Expert Solution

Step 1

Given:-

The span length of the beam = 7 m

The superimposed dead load = 28 kN/m

The live load = X = 1424 N/m

The unit weight of the concrete = 24 kN/m²

The concrete strength (f'c) = 40 MPa

The steel strength (fy) = 400 MPa

To determine:-

The area of the steel using $ρ_{m a x}$

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