Structural Equation: NH₂ Jau il CH3 + Stoichiometric Equation CuHy CH3Nha + (CH3CO) 0 Mass of acetic anhydride Mass of o-toluidine NH CH3 Just CH3 1.3 mL | 1.089 = 1.404g (CH3CO) ₂0 IML o-toluidine 1.004 g 1 mol 107.159 CaHO+ CH3COOH 1ML 1.004g = 1.004g C6H IML * o-toluidine is limiting reactant Theoretical Yield Limiting Reactant acetic anhydride 1.404g Imol = 0.0138 mol (CH3CO)₂0 102.09g OH = 0.0094 mol C6H4 CH 3 NH ₂ 149.199 Imol C₂H4CH3NH₂ 1 mol CqH₁10 0.0094 C6H4CH3NH₂ 1 mol C9H₁₁0 D = 1.40g Cq H₁, 0
Structural Equation: NH₂ Jau il CH3 + Stoichiometric Equation CuHy CH3Nha + (CH3CO) 0 Mass of acetic anhydride Mass of o-toluidine NH CH3 Just CH3 1.3 mL | 1.089 = 1.404g (CH3CO) ₂0 IML o-toluidine 1.004 g 1 mol 107.159 CaHO+ CH3COOH 1ML 1.004g = 1.004g C6H IML * o-toluidine is limiting reactant Theoretical Yield Limiting Reactant acetic anhydride 1.404g Imol = 0.0138 mol (CH3CO)₂0 102.09g OH = 0.0094 mol C6H4 CH 3 NH ₂ 149.199 Imol C₂H4CH3NH₂ 1 mol CqH₁10 0.0094 C6H4CH3NH₂ 1 mol C9H₁₁0 D = 1.40g Cq H₁, 0
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Can you check my prelab work for ochem
Lab is the preparation of an acetamide
our reactanct are o-toluidine and acetic anhydride
we will use 1.3 mL of acetic anhydride and 1.0 mL of o-toluidine
Please check that my structural equation and stoichiometric equation is correct and then check my other equations.
also, what is the name for the product
I've found multiple but wasn't sure which one to use...
2-methyl acetanilide
N-(methyphenyl) acetamide
o-acetotoluidide
Transcribed Image Text:Structural Equation:
NH₂
Jou li
CH3
+
Stoichiometric Equation
CuHy CH3Nha + (CH3CO) 0 CaHO+ CH3COOH DS
Mass of acetic anhydride
Mass of o-toluidine
o-toluidine
NH
CH3
Jyor. Son
CH3
OH
1.3 mL | 1.089 = 1.404g (CH3CO) ₂0
IML
→>>
IML 1.004g = 1.004g C6H
IML
Limiting Reactant
acetic anhydride 1.404g Imol = 0.0138 mol (CH3CO)₂0
(02.09g
1.004 g 1 mol
* o-toluidine is limiting reactant
Theoretical Yield
107.15g
=
0.0094 mol C6H4CH 3 NH ₂
149.199
Imol C₂H4CH3NH₂ 1 mol CqH₁10
0.0094 CH4CH3NH₂ 1 mol C9H₁₁0
= 1.40g Cq H₁, 0
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