String Refinement Fill in the refineStringArray method so that it returns an array of all the Strings in the given array that have length greater or equal to the length of a given string. If the array is null or empty, or the given string is null, return null. The output strings should be in the same order they appear in the original array. Note that if the array contains any null element, then you need to skip that null element. Example 1 refineStringArray (new String[] {"Hello World", "a", "abc"}, "oop") should return {"Hello World", "abc"} public class StringRefinement{ public static String[] refineStringArray (String[] strings, String toCompare) { refineStringArray (new String[] {"Hello World", "a", "abc"}, null); for (int i=0;i

EBK JAVA PROGRAMMING
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Chapter9: Advanced Array Concepts
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Can you help me fix my code in Java, please? I am stuck to keep going.

Thank you

String Refinement
to
Fill in the refineStringArray method so that it returns an array of
all the Strings in the given array that have length greater or equal
the length of a given string. If the array is null or empty, or the given
string is null, return null. The output strings should be in the same
order they appear in the original array. Note that if the array contains
any null element, then you need to skip that null element.
Example 1
refineStringArray (new String[] {"Hello World", "a", "abc"}, "oop")
should return
{"Hello World", "abc"}
Example 2
refineStringArray (new String[] {"a", "ab", "abc"}, "java")
should return
{}
Example 3
refineStringArray (new String[] {"Hello World", "a", "abc"}, null)
should return
null
1 public class StringRefinement {
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7896
10
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14
public static String[] refineStringArray (String[] strings, String toCompare) {
refineStringArray (new String[] {"Hello World", "a", "abc"}, null);
for (int i=0;i<strings.length; i++) {
if(string[i]==String toCompare) return 1;
return null;
}
}
public static void main(String[] args) {
refineStringArray();
}
/home/StringRefinement.java 14:2 Tabs (Auto)
Terminal
[user@sahara ~]$ java StringRefinement.java
StringRefinement.java:6: error: ')' expected
if(string[i]==String toCompare) return 1;
A
StringRefinement.java:6: error: not a statement
if(string[i]==String toCompare) return 1;
A
StringRefinement.java:6: error: ';' expected
if(string[i]==String toCompare) return 1;
Transcribed Image Text:String Refinement to Fill in the refineStringArray method so that it returns an array of all the Strings in the given array that have length greater or equal the length of a given string. If the array is null or empty, or the given string is null, return null. The output strings should be in the same order they appear in the original array. Note that if the array contains any null element, then you need to skip that null element. Example 1 refineStringArray (new String[] {"Hello World", "a", "abc"}, "oop") should return {"Hello World", "abc"} Example 2 refineStringArray (new String[] {"a", "ab", "abc"}, "java") should return {} Example 3 refineStringArray (new String[] {"Hello World", "a", "abc"}, null) should return null 1 public class StringRefinement { 123456 7896 10 11 12 13 14 public static String[] refineStringArray (String[] strings, String toCompare) { refineStringArray (new String[] {"Hello World", "a", "abc"}, null); for (int i=0;i<strings.length; i++) { if(string[i]==String toCompare) return 1; return null; } } public static void main(String[] args) { refineStringArray(); } /home/StringRefinement.java 14:2 Tabs (Auto) Terminal [user@sahara ~]$ java StringRefinement.java StringRefinement.java:6: error: ')' expected if(string[i]==String toCompare) return 1; A StringRefinement.java:6: error: not a statement if(string[i]==String toCompare) return 1; A StringRefinement.java:6: error: ';' expected if(string[i]==String toCompare) return 1;
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