8.3: t Test for Mean: Population Standard Deviation UnknownScore: 4.55/114/11 answeredProgre• Question 5>You wish to test the following claim (H1) at a significance level of a = 0.05.H.:µ = 58.7H1:µ > 58.7You believe the population is normally distributed, but you do not know the standard deviation. You obtaina sample of size n = 9 with mean = 75.3 and a standard deviation ofs = 17.2.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic =What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =The p-value is...O less than (or equal to) aO greater than aThis test statistic leads to a decision to...O reject the nullO accept the nullO fail to reject the nullAs such, the final conclusion is that...O There is sufficient evidence to warrant rejection of the claim that the population mean is greaterthan 58.7.O There is not sufficient evidence to warrant rejection of the claim that the population mean isgreater than 58.7.MacBook Air80DIIF3F4F5F6F7F8F9F10#32$&*()345789EYP< cO

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Answered: 8.3: t Test for Mean: Population…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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H0:μ=25.735H0:μ=25.735H1:μ≠25.735H1:μ≠25.735Your sample consists of 46 subjects, with a mean of 24 and a standard deviation of 4.73 Calculate the test statistic, rounded to 2 decimal places
The manufacturer claims that your new car gets 28 mpg on the highway. You suspect that the mpg is more for your car. The 66 trips on the highway that you took averaged 32 mpg and the standard deviation for these 66 trips was 10.9 mpg. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion Correct The null and alternative hypotheses would be: H0:H0: ? p μ CorrectSelect an answer ≤ = ≥ ≠ Ha:Ha: ? μ p CorrectSelect an answer = < > ≠ The test statistic ? z t Correct = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > Correct αα Based on this, we should Select an answer accept fail to reject reject Incorrect the null hypothesis. Thus, the final conclusion is that ... The data suggest that the sample mean is not significantly more than 28 at αα = 0.05, so there is…
The average salary in this city is $43,200. Is the average more for single people? 47 randomly selected single people who were surveyed had an average salary of $49,485 and a standard deviation of $16,570. What can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer ≠ < = > H1:H1: ? p μ Select an answer > ≠ = < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis.
Aspirin is packed in 120 tab bottles with weight normally distributed with mean 600g and standard deviation 6g. Rejected bottles are those whose weight differs from the mean weight by 15g or more. That is, rejected bottles have weight either too small or too large. We want to find out how many bottles will be rejected from a daily production of 5000 bottles. 1,Do we have to calculate one z-score or two z-scores? 2. The negative z-score is 3. The positive z-score is 4.How many bottles, of the 5000, do we anticipate to have to reject?
You wish to test the following claim (Ha) at a significance level of α=0.01. Ho:μ=88.9Ha:μ>88.9 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=17 with mean ¯x=98.1 and a standard deviation of s=18.9 What is the test statistic for this sample? test statistic = Round to 3 decimal places What is the p-value for this sample? p-value = Round to 4 decimal places.
Just the incorrect answers please
You wish to test the following claim (Ha) at a significance level of a = 0.001. Ho:µ = 60.5 Ha:µ + 60.5 You believe the population is normally distributed and you know the standard deviation is o = 11.1 You obtain a sample mean of M = 56.9 for a sample of size n = 39. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is. O less than (or equal to) a O greater than a This test statistic leads to a decision to... O reject the null O accept the null O fail to reject the null As such, the final conclusion is that... O There is sufficient evidence to warrant rejection of the claim that the population mean is not equal to 60.5. O There is not sufficient evidence to warrant rejection of the claim that the population mean is not equal to 60.5. O The sample data support the claim that the population mean is not equal to 60.5. O…
The average salary for American college graduates is $45,100. You suspect that the average is less for graduates from your college. The 50 randomly selected graduates from your college had an average salary of $42,788 and a standard deviation of $5,940. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < = ≠ H1:H1: ? p μ Select an answer ≠ > = < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer fail to reject reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest that the population mean is not significantly less than 45,100 at αα = 0.05, so there is…

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