**Hypothesis Testing Example** You wish to test the null hypothesis $ H_0: \mu = 53.2 $ versus the alternative hypothesis $ H_a: \mu > 53.2 $ at a significance level of 0.01. You obtain a sample of size 16 with a mean of 54.4 and a standard deviation of 8.2. You believe that the population is normally distributed.Round your answers to three decimal places, and round any interim calculations to four decimal places.**Question**: What is the test statistic? [Enter your answer in the provided box]

Answered: You wish to test Ho:μ = 53.2 versus…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following claim (Ha) at a significance level of a = 0.01. H.:µ = 73.7 HaiH + 73.7 You believe the population is normally distributed, but you do not know the standard deviation. Your sample has: size: n = 54 mean: M = 65.8 standard deviation: SD = 20.1. What is the test statistic for this sample? (Round the answer accurate to 3 decimal places.) test statistic: t = What is the P-value for this sample? (Round the answer accurate to 3 decimal places.) P-value = The P-value is... less than (or equal to) a greater than a This leads to a decision to... reject the null accept the null fail to reject the null So, the final conclusion is that... The data do not support the claim of the alternative hypothesis that the population mean is not equal to 73.7. The sample data support the claim of the alternative hypothesis that the population mean is not equal to 73.7.
i need C and D
answer the blanks 1,2,3,4
This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
You wish to test the following claim (Ha) at a significance level of a = 0.05 Ho: 82.5 Ha: 82.5 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n 50 with mean M 77.3 and a standard deviation of SD 18.4. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value The p-value is.. less than (or equal to) a greater than a This test statistic leads to a decision to... Oreject the null accept the null Ofail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is less than 82.5 There is not sufficient evidence to warrant rejection of the claim that the population mean is less than 82.5. The sample data support the claim that the population mean is less than 82.5 There is not…
You wish to test the following claim (Ha) at a significance level of a = 0.005. H.: µ = 60.8 H.:u > 60.8 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 92.4 61.2 97.2 82.3 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) a O greater than a This test statistic leads to a decision to... o reject the null o accept the null o fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 60.8. There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 60.8. The sample data support the claim that the population mean is greater than 60.8. There is…
You wish to test the following claim (HA) at a significance level of a = 0.002. H.:µ = 76.5 Ha: µ > 76.5 You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n = 16 with mean M = 95.2 and a standard deviation of SD = 18.2. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = 4.1099 V What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value =
You wish to test the following claim (H.) at a significance level of a = 0.01. H.:µ = 75.8 Ha:µ > 75.8 You believe the population is normally distributed, but you do not know the standard deviation. Your sample has: size: n = 73 mean: M = 77.2 standard deviation: SD = 8.5. What is the test statistic for this sample? (Round the answer accurate to 3 decimal places.) test statistic: t = What is the P.value for this sample? (Round the answer accurate to 3 decimal places.) P-value = The P-value is... O less than (or equal to) a O greater than a This leads to a decision to... O reject the null O accept the null O fail to reject the null So, the final conclusion is that... O The data do not support the claim of the alternative hypothesis that the population mean is greater than 75.8. O The sample data support the claim of the alternative hypothesis that the population mean is greater than 75.8.
You wish to test the following claim (Ha) at a significance level of a = 0.005. H,:µ = 90.6 Ha:µ < 90.6 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 95.7 78.9 81.3 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... Oless than (or equal to) a greater than a
You conduct a between-subjects ANOVA investigating whether different states produce tastier cheeses. You find that eta-squared is .50. What does this tell you? a. The effect size is small. b. 50% of the total variance in tastiness is due to differences between the states. c. The difference between the group means is .50 standard deviations. d. All of the above
In the 1992 presidential election, Alaska's 40 election districts averaged 2002 votes per district for President Clinton. The standard deviation was 566. (There are only 40 election districts in Alaska.) The distribution of the votes per district for President Clinton was bell-shaped. Let X = number of votes for President Clinton for an election district. (Source: The World Almanac and Book of Facts) Round all answers except part e. to 4 decimal places. Find the third quartile for votes for President Clinton. Round your answer to the nearest whole number.
Is the difference between the mean annual salaries of entry level architects in Denver, Colorado, and Lincoln, Nebraska, equal to $10,500? To decide, you select a random sample of entry level architects from each city. The results of each survey are shown. Assume the population standard deviations are o₁ =$6511 and 2 = $6192. At a = 0.01, what should you conclude? Entry level architects Entry level architects in Denver, CO x₁ = 58,300 n₁ = 39 In Lincoln, NE x2 = 54,240 n2 = 30 What are the null and alternative hypotheses for this test? OA. Ho: H₁₂ = 10,500 Ha: H₁-H2*10,500 OD. Ho: P₁-H2>10,500 Ha: H1-H₂s 10,500 Calculate the standardized test statistic. z= (Round to two decimal places as needed.) Determine the P-value. The P-value is (Round to three decimal places as needed.) What can you conclude about the data? OB. Ho: H1 H2S 10,500 Ha H1-H2>10,500 OC. Ho: H1 H2210,500 Ha H1-H2 <10,500 OE. Ho: H1 H2*10,500 Ha: 1-2=10,500 OA. Reject Ho. At the 1% level of significance, there is…

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