State the appropriate null and alternative hypotheses. ⒸHg: H₁ H₂ = 0 Hoi H₂-H₂0 H₂H₂H₂ = 0 Hot H₁ H₂ = 0 H₂H₂H₂O ON :H1-12 30 H₂H₂H₂ = 0 ⒸH₂H₁-H₂=0 Find the test statistic. (Round your answer to two decimal places.) t= Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 0.0000
State the appropriate null and alternative hypotheses. ⒸHg: H₁ H₂ = 0 Hoi H₂-H₂0 H₂H₂H₂ = 0 Hot H₁ H₂ = 0 H₂H₂H₂O ON :H1-12 30 H₂H₂H₂ = 0 ⒸH₂H₁-H₂=0 Find the test statistic. (Round your answer to two decimal places.) t= Use technology to find the P-value. (Round your answer to four decimal places.) P-value = 0.0000
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Many people now turn to the internet to get information on health-related topics. A research article used Flesch reading ease scores (a measure of reading difficulty based on factors such as sentence length and number of syllables in the words used) to score pages on
Wikipedia and on WebMD. Higher Flesch scores correspond to more difficult reading levels. The paper reported that for a representative sample of health-related pages on Wikipedia, the mean Flesch score was 26.3 and the standard deviation of the Flesch scores was
14.3. For a representative sample of pages from WebMD, the mean score was 43.3 and the standard deviation was 19.6. Suppose that these means and standard deviations were based on samples of 40 pages from each site. Is there convincing evidence that the mean
reading level for health-related pages differs for Wikipedia and WebMD? Test the relevant hypotheses using a significance level of 0.05. (Use ₁ for Wikipedia and #₂ for WebMD.)
State the appropriate null and alternative hypotheses.
ⒸH₁ H₁-H₂=0
H₂! H₂-H₂ > 0
Hoi H₂-H₂ 20
H₂H₂H₂ = 0
Hoi H₁ H₂ = 0
O
USE SALT
о
NO: Hi-H2CO
H₂H₂ H₂ = 0
но: H-H2=0
H₂H₂H₂ <0
Find the test statistic. (Round your answer to two decimal places.)
t = [
Use technology to find the P-value. (Round your answer to four decimal places.)
P-value= 0.0000✔
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