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According to a poll, 11.55% of adults in a certain country have diabetes. Suppose a researcher wonders if the diabetes rate in her area is higher than the national rate. She surveys 122 adults in her area and finds that 18 of them have diabetes. Complete parts a and b below. z = ± 1.1073 p = 0.2682 z = 1.1073 p=0.8659 B. If 11.55% of the adults in this area have diabetes, then there is a - 1.1073 or greater than 1.1073. Interpret the p-value. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or decimal rounded to two decimal places as needed.) A. There is a chance that more than 18 out of 122 people in this area have diabetes. C. If 11.55% of the adults in this area have diabetes, then there is a 1.1073 or less. z = 1.1073 D. If 11.55% of adults in this area have diabetes, then there is a greater. p = 0.1341 % chance of observing a z-score less than % chance of observing a z-score of % chance of observing a z-score of 1.1073 or

According to a poll, 11.55% of adults in a certain country have diabetes. Suppose a researcher wonders if the diabetes rate in her area is higher than the national rate. She surveys 122 adults in her area and finds that 18 of them have diabetes. Complete parts a and b below. z = ± 1.1073 p = 0.2682 z = 1.1073 p=0.8659 B. If 11.55% of the adults in this area have diabetes, then there is a - 1.1073 or greater than 1.1073. Interpret the p-value. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or decimal rounded to two decimal places as needed.) A. There is a chance that more than 18 out of 122 people in this area have diabetes. C. If 11.55% of the adults in this area have diabetes, then there is a 1.1073 or less. z = 1.1073 D. If 11.55% of adults in this area have diabetes, then there is a greater. p = 0.1341 % chance of observing a z-score less than % chance of observing a z-score of % chance of observing a z-score of 1.1073 or

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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According to a poll, 11.55% of adults in a certain country have diabetes. Suppose a researcher wonders if the diabetes rate in her area is higher than the national rate. She surveys 122 adults in her area and finds that 18 of them have diabetes. Complete parts a and b below. z = ± 1.1073 p = 0.2682 z = 1.1073 p=0.8659 B. If 11.55% of the adults in this area have diabetes, then there is a - 1.1073 or greater than 1.1073. Interpret the p-value. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or decimal rounded to two decimal places as needed.) A. There is a chance that more than 18 out of 122 people in this area have diabetes. OC. If 11.55% of the adults in this area have diabetes, then there is a 1.1073 or less. z = 1.1073 D. If 11.55% of adults in this area have diabetes, then there is a greater. p = 0.1341 % chance of observing a z-score less than % chance of observing a z-score of % chance of observing a z-score of 1.1073 or
Transcribed Image Text:According to a poll, 11.55% of adults in a certain country have diabetes. Suppose a researcher wonders if the diabetes rate in her area is higher than the national rate. She surveys 122 adults in her area and finds that 18 of them have diabetes. Complete parts a and b below. z = ± 1.1073 p = 0.2682 z = 1.1073 p=0.8659 B. If 11.55% of the adults in this area have diabetes, then there is a - 1.1073 or greater than 1.1073. Interpret the p-value. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or decimal rounded to two decimal places as needed.) A. There is a chance that more than 18 out of 122 people in this area have diabetes. OC. If 11.55% of the adults in this area have diabetes, then there is a 1.1073 or less. z = 1.1073 D. If 11.55% of adults in this area have diabetes, then there is a greater. p = 0.1341 % chance of observing a z-score less than % chance of observing a z-score of % chance of observing a z-score of 1.1073 or
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