0.5 1 1.5 2.5 b. 572 330 h(q) 190 110 63 Estimate h' (1.5) using the table. Give your estimate rounded to one decimal place. h'(1.5) Submit Question

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Understanding Derivatives from a Table

Given a table of values for a function \( h(q) \), we want to estimate \( h'(1.5) \), the derivative of \( h \) at \( q = 1.5 \), by using numerical methods. The table provided is:

| \( q \)  | 0.5 | 1   | 1.5 | 2   | 2.5 |
|----------|-----|-----|-----|-----|-----|
| \( h(q) \)| 572 | 330 | 190 | 110 | 63  |

### Instructions

1. **Select Points for Approximation**: To estimate \( h'(1.5) \), we select points around \( q = 1.5 \). A natural choice is to use \( q = 1 \) and \( q = 2 \).

2. **Apply the Slope Formula**: The derivative can be approximated by the slope between two points:
   \[
   h'(q) \approx \frac{h(q_2) - h(q_1)}{q_2 - q_1}
   \]
   Substitute \( q_1 = 1 \) and \( q_2 = 2 \):
   \[
   h'(1.5) \approx \frac{h(2) - h(1)}{2 - 1} = \frac{110 - 330}{2 - 1}
   \]
   \[
   h'(1.5) \approx \frac{-220}{1} = -220
   \]

3. **Round Your Answer**: The estimate should be rounded to one decimal place.

### Conclusion

By using this method, we derive a numerical approximation for the derivative at a given point using a simple linear slope between adjacent data points. The estimated value of \( h'(1.5) \) is approximately \(-220.0\).

#### Input Field

- Enter your answer: \(-220.0\)

#### Action Button

- Submit your estimate using the “Submit Question” button to verify the accuracy of your calculation.
Transcribed Image Text:### Understanding Derivatives from a Table Given a table of values for a function \( h(q) \), we want to estimate \( h'(1.5) \), the derivative of \( h \) at \( q = 1.5 \), by using numerical methods. The table provided is: | \( q \) | 0.5 | 1 | 1.5 | 2 | 2.5 | |----------|-----|-----|-----|-----|-----| | \( h(q) \)| 572 | 330 | 190 | 110 | 63 | ### Instructions 1. **Select Points for Approximation**: To estimate \( h'(1.5) \), we select points around \( q = 1.5 \). A natural choice is to use \( q = 1 \) and \( q = 2 \). 2. **Apply the Slope Formula**: The derivative can be approximated by the slope between two points: \[ h'(q) \approx \frac{h(q_2) - h(q_1)}{q_2 - q_1} \] Substitute \( q_1 = 1 \) and \( q_2 = 2 \): \[ h'(1.5) \approx \frac{h(2) - h(1)}{2 - 1} = \frac{110 - 330}{2 - 1} \] \[ h'(1.5) \approx \frac{-220}{1} = -220 \] 3. **Round Your Answer**: The estimate should be rounded to one decimal place. ### Conclusion By using this method, we derive a numerical approximation for the derivative at a given point using a simple linear slope between adjacent data points. The estimated value of \( h'(1.5) \) is approximately \(-220.0\). #### Input Field - Enter your answer: \(-220.0\) #### Action Button - Submit your estimate using the “Submit Question” button to verify the accuracy of your calculation.
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