Find P(CNE) directly from the table. B C Totals 0.08 0.04 0.08 0.20 E 0.42 0.26 0.12 0.80 Totals 0.50 0.30 0.20 1.00
Find P(CNE) directly from the table. B C Totals 0.08 0.04 0.08 0.20 E 0.42 0.26 0.12 0.80 Totals 0.50 0.30 0.20 1.00
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![The table provided is used to calculate the probability of joint events. It shows probabilities for combinations of events, organized as follows:
**Table Columns and Rows:**
- **Columns:** Represent categories A, B, and C, with a Totals column for each.
- **Rows:** Represent categories D and E, with a Totals row for each.
**Table Values:**
- The probability values for each combination are as follows:
- P(D∩A) = 0.08
- P(D∩B) = 0.04
- P(D∩C) = 0.08
- Total for D = 0.20
- P(E∩A) = 0.42
- P(E∩B) = 0.26
- P(E∩C) = 0.12
- Total for E = 0.80
- **Column Totals:**
- Total for A = 0.50
- Total for B = 0.30
- Total for C = 0.20
- **Overall Total:** 1.00
The field below the table asks for the probability P(C∩E), which is found directly in the table at the intersection of row E and column C.
**Answer:**
P(C∩E) = 0.12
This text and table should help in understanding joint probability and how to read such tables.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffd12fdfe-1c89-4137-ae62-d4bc4403459c%2F34a4bf7b-35fd-47a7-aa69-45aa8968ff0c%2Fab3wy3g_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The table provided is used to calculate the probability of joint events. It shows probabilities for combinations of events, organized as follows:
**Table Columns and Rows:**
- **Columns:** Represent categories A, B, and C, with a Totals column for each.
- **Rows:** Represent categories D and E, with a Totals row for each.
**Table Values:**
- The probability values for each combination are as follows:
- P(D∩A) = 0.08
- P(D∩B) = 0.04
- P(D∩C) = 0.08
- Total for D = 0.20
- P(E∩A) = 0.42
- P(E∩B) = 0.26
- P(E∩C) = 0.12
- Total for E = 0.80
- **Column Totals:**
- Total for A = 0.50
- Total for B = 0.30
- Total for C = 0.20
- **Overall Total:** 1.00
The field below the table asks for the probability P(C∩E), which is found directly in the table at the intersection of row E and column C.
**Answer:**
P(C∩E) = 0.12
This text and table should help in understanding joint probability and how to read such tables.
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