"Next" to continue working on this unit -6 da A researcher wants to show that the proportion of mosquitoes that carry a certain disease is greater in Region 1 than Region 2. In a sample of 1,323 mosquitoes apped in Region 1, 1,045 test positive for the disease. In a sample of 1,5. mosquitoes trapped in Region 2, 1,189 test positive for the disease. Test the alternative hypothesis that the population proportion for Region 1 is greater than the population proportion for Region 2. The test statistic is z = 1.62. What is th correspondingp-value? Compute your answer using a value from the table below. z0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 1.00.841 0.844 0.846 0.848 0.851 0.8530.8550.858 0.8600.862 1.1 0.864 0.8670.869 0.8710.8730.875 0.877 0.879 0.881 0.883 1.2 0.885 0.887 0.889 0.891 0.893 0.894 0.896 0.898 0.9000.901 1.3 0.903 0.905 0.907 0.9080.9100.911 0.913 0.9150.916 0.918 1.4 0.919 0.921 0.922 0.9240.925 0.926|0.928 0.929 0.9310.932 1.5 0.933 0.934 0.936 0.9370.938 0.939 0.941 0.942 0.943 0.944 1.6 0.945 0.946 0.947 0.948 0.949 0.951 0.952 0.953 0.9540.954

MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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**Text Transcription: Educational Website Format**

**Title: Statistical Analysis of Mosquito Populations in Regions**

**Introduction:**

A research study aims to determine if the proportion of mosquitoes carrying a particular disease is higher in Region 1 compared to Region 2. Data from mosquito samples gathered in each region are analyzed to draw conclusions about the regional differences in disease prevalence.

**Data Summary:**

- **Region 1 Sample:**
  - Total mosquitoes trapped: 1,323
  - Mosquitoes testing positive for the disease: 1,045

- **Region 2 Sample:**
  - Total mosquitoes trapped: 1,559
  - Mosquitoes testing positive for the disease: 839

**Research Objective:**
The objective is to test the hypothesis that the proportion of disease-carrying mosquitoes in Region 1 is greater than in Region 2.

**Statistical Approach:**
- **Test Statistic:** \( z = 1.62 \)
- The task involves determining the corresponding \( p \)-value using a standard normal distribution (z-table).

**Z-Table Analysis:**

An accompanying z-table is provided to find the \( p \)-value for the test statistic. The table format displays z-scores at varying decimal levels, allowing precise determination of statistical significance:

```
   z \  0.00  0.01  0.02  ...
  1.0  0.841  0.844  0.846
  1.1  0.864  0.867  0.869
  1.2  0.885  0.888  0.891
  1.3  0.903  0.905  0.908
  1.4  0.919  0.921  0.922
  1.5  0.933  0.935  0.937
  1.6  0.945  0.947  0.948
```

**Instructions for \( p \)-Value Computation:**

Locate the z-score of 1.62 in the table, using the row for 1.6 and the column for 0.02 to find the corresponding \( p \)-value. This value demonstrates the probability that the observed statistical result could occur
Transcribed Image Text:**Text Transcription: Educational Website Format** **Title: Statistical Analysis of Mosquito Populations in Regions** **Introduction:** A research study aims to determine if the proportion of mosquitoes carrying a particular disease is higher in Region 1 compared to Region 2. Data from mosquito samples gathered in each region are analyzed to draw conclusions about the regional differences in disease prevalence. **Data Summary:** - **Region 1 Sample:** - Total mosquitoes trapped: 1,323 - Mosquitoes testing positive for the disease: 1,045 - **Region 2 Sample:** - Total mosquitoes trapped: 1,559 - Mosquitoes testing positive for the disease: 839 **Research Objective:** The objective is to test the hypothesis that the proportion of disease-carrying mosquitoes in Region 1 is greater than in Region 2. **Statistical Approach:** - **Test Statistic:** \( z = 1.62 \) - The task involves determining the corresponding \( p \)-value using a standard normal distribution (z-table). **Z-Table Analysis:** An accompanying z-table is provided to find the \( p \)-value for the test statistic. The table format displays z-scores at varying decimal levels, allowing precise determination of statistical significance: ``` z \ 0.00 0.01 0.02 ... 1.0 0.841 0.844 0.846 1.1 0.864 0.867 0.869 1.2 0.885 0.888 0.891 1.3 0.903 0.905 0.908 1.4 0.919 0.921 0.922 1.5 0.933 0.935 0.937 1.6 0.945 0.947 0.948 ``` **Instructions for \( p \)-Value Computation:** Locate the z-score of 1.62 in the table, using the row for 1.6 and the column for 0.02 to find the corresponding \( p \)-value. This value demonstrates the probability that the observed statistical result could occur
**Educational Website Content**

---

**Homework Assignment Rubric**

This assignment is worth 10 points. Knewton Alta automatically grades your assignment based on the percentage of right answers.
Transcribed Image Text:**Educational Website Content** --- **Homework Assignment Rubric** This assignment is worth 10 points. Knewton Alta automatically grades your assignment based on the percentage of right answers.
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