Starting with the following equation, BaCl2(aq) + Na,PO.(aq) → Ba3(PO4)2(s) + NaCI(aq) calculate the mass in grams of BaCl, that will be required to produce 69.5 grams of Ba3(PO4)2.
Starting with the following equation, BaCl2(aq) + Na,PO.(aq) → Ba3(PO4)2(s) + NaCI(aq) calculate the mass in grams of BaCl, that will be required to produce 69.5 grams of Ba3(PO4)2.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Chemical Reaction Stoichiometry Calculation
To determine the mass of \(\text{BaCl}_2\) needed to produce 69.5 grams of \(\text{Ba}_3(\text{PO}_4)_2\), start with the balanced chemical equation:
\[
\text{3BaCl}_2(\text{aq}) + \text{2Na}_3\text{PO}_4(\text{aq}) \rightarrow \text{Ba}_3(\text{PO}_4)_2(\text{s}) + \text{6NaCl}(\text{aq})
\]
### Steps for Calculation:
1. **Molar Mass Calculation:**
- Calculate the molar mass of \(\text{Ba}_3(\text{PO}_4)_2\).
\[
\text{Ba}_3(\text{PO}_4)_2: 3(137.33) + 2(30.97 + 4(16)) = 601.93 \, \text{g/mol}
\]
2. **Convert Grams to Moles:**
- Convert grams of \(\text{Ba}_3(\text{PO}_4)_2\) to moles.
\[
\text{Moles of Ba}_3(\text{PO}_4)_2 = \frac{69.5 \, \text{g}}{601.93 \, \text{g/mol}} \approx 0.115 \, \text{moles}
\]
3. **Use Stoichiometry to Find Moles of \(\text{BaCl}_2\):**
- Use the mole ratio from the balanced equation to find moles of \(\text{BaCl}_2\).
\[
\frac{3 \, \text{moles BaCl}_2}{1 \, \text{mole Ba}_3(\text{PO}_4)_2} = 0.345 \, \text{moles of BaCl}_2
\]
4. **Calculate Mass of \(\text{BaCl}_2\):**
- Find the molar mass of \(\text{BaCl}_2\).
\[
\text{BaCl}_2: 137.33 + 2(35.45) = 208.23 \, \text{g/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F53917c9e-ccf4-4185-ada8-2f03b0536363%2F03502f9f-13a5-4df9-886f-77f26350ee05%2Fwowss1u_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Chemical Reaction Stoichiometry Calculation
To determine the mass of \(\text{BaCl}_2\) needed to produce 69.5 grams of \(\text{Ba}_3(\text{PO}_4)_2\), start with the balanced chemical equation:
\[
\text{3BaCl}_2(\text{aq}) + \text{2Na}_3\text{PO}_4(\text{aq}) \rightarrow \text{Ba}_3(\text{PO}_4)_2(\text{s}) + \text{6NaCl}(\text{aq})
\]
### Steps for Calculation:
1. **Molar Mass Calculation:**
- Calculate the molar mass of \(\text{Ba}_3(\text{PO}_4)_2\).
\[
\text{Ba}_3(\text{PO}_4)_2: 3(137.33) + 2(30.97 + 4(16)) = 601.93 \, \text{g/mol}
\]
2. **Convert Grams to Moles:**
- Convert grams of \(\text{Ba}_3(\text{PO}_4)_2\) to moles.
\[
\text{Moles of Ba}_3(\text{PO}_4)_2 = \frac{69.5 \, \text{g}}{601.93 \, \text{g/mol}} \approx 0.115 \, \text{moles}
\]
3. **Use Stoichiometry to Find Moles of \(\text{BaCl}_2\):**
- Use the mole ratio from the balanced equation to find moles of \(\text{BaCl}_2\).
\[
\frac{3 \, \text{moles BaCl}_2}{1 \, \text{mole Ba}_3(\text{PO}_4)_2} = 0.345 \, \text{moles of BaCl}_2
\]
4. **Calculate Mass of \(\text{BaCl}_2\):**
- Find the molar mass of \(\text{BaCl}_2\).
\[
\text{BaCl}_2: 137.33 + 2(35.45) = 208.23 \, \text{g/mol
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