Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.317g copper metal was obtained as an experimental result according to the equation: CuSO4(aq) + Zn(s) →Cu(s) + ZNSO4(aq) Before the experiment was carried out the following calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu. mol g Cuso mol Cu g Cu Cuso, 1 mol CuSO, 1 mol Cu 63.55 g Cu 159.62 g CusO4 1 тol CuSO, 1 тol Cu What is the percent yield? report your answer to the tenths place, i.e. one decimal place.
Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.317g copper metal was obtained as an experimental result according to the equation: CuSO4(aq) + Zn(s) →Cu(s) + ZNSO4(aq) Before the experiment was carried out the following calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu. mol g Cuso mol Cu g Cu Cuso, 1 mol CuSO, 1 mol Cu 63.55 g Cu 159.62 g CusO4 1 тol CuSO, 1 тol Cu What is the percent yield? report your answer to the tenths place, i.e. one decimal place.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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![Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.317 g copper metal was obtained as an
experimental result according to the equation:
CuSO4(aq) + Zn(s) → Cu(s) + ZnSO4(aq)
Before the experiment was carried out the following calculation was completed to predict the maximum amount
of copper that could be isolated. The answer was 0.506g of Cu.
mol
g CuSO
mol Cu
g Cu
CuSO
1 mol CuSO4
1 mol Cu
1 тol CusO,
63.55 g Cu
159.62 g CuSO4
1 mol Cu
What is the percent yield?
report your answer to the tenths place, i.e. one decimal place.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5d11609e-452d-4faf-9e92-329dfa026e1e%2Faf0fb1ad-457a-49d8-ba0d-d6a72c95b563%2Fpibudj9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.317 g copper metal was obtained as an
experimental result according to the equation:
CuSO4(aq) + Zn(s) → Cu(s) + ZnSO4(aq)
Before the experiment was carried out the following calculation was completed to predict the maximum amount
of copper that could be isolated. The answer was 0.506g of Cu.
mol
g CuSO
mol Cu
g Cu
CuSO
1 mol CuSO4
1 mol Cu
1 тol CusO,
63.55 g Cu
159.62 g CuSO4
1 mol Cu
What is the percent yield?
report your answer to the tenths place, i.e. one decimal place.
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