Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 300 75 14.07 Error 160 30 5.333 Total 460 34 a. What hypotheses are implied in this problem? Họ: All five treatment means are equal H: Not all five treatment means are equal b. At the a = 0.05 level of significance, can we reject the null hypothesis in part (a)? Calculate the value of the test statistic (to 2 decimals). The p-value is between 0.01 and 0.025 What is your conclusion? Conclude not all five treatment means are equal v
Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value Treatments 300 75 14.07 Error 160 30 5.333 Total 460 34 a. What hypotheses are implied in this problem? Họ: All five treatment means are equal H: Not all five treatment means are equal b. At the a = 0.05 level of significance, can we reject the null hypothesis in part (a)? Calculate the value of the test statistic (to 2 decimals). The p-value is between 0.01 and 0.025 What is your conclusion? Conclude not all five treatment means are equal v
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:In a completely randomized design, seven experimental units were used for each of the five levels of the factor. Complete the following ANOVA table (to 2 decimals, if necessary). If your answer is zero enter "0".
Source of Variation Sum of Squares Degrees of Freedom Mean Square
F
p-value
Treatments
300
4
75
14.07
Error
160
30
5.333
Total
460
34
a. What hypotheses are implied in this problem?
Ho: All five treatment means are equal
H: Not all five treatment means are equal v
b. At the a = 0.05 level of significance, can we reject the null hypothesis in part (a)?
Calculate the value of the test statistic (to 2 decimals).
The p-value is between 0.01 and 0.025 v
What is your conclusion?
Conclude not all five treatment means are equal v
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