esidual 846.2 15 56.4   Total 3226.6 17     Group of answer choices We reject  H0 because 21.1 ≥ 3.68. We have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments. We reject  H0 because 21.1 ≥ 3.29. We have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments. We reject  H0 because 21.1 ≥ 3.68. We do not have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments. We do not reject  H0 because 21.1 ≥ 3.68. We have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
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Question

According to the ANOVA table below for mean systolic blood pressure treatments, a proper conclusion will be:

 

Source of

variation

 

Sums of Squares

(SS)

Degrees of freedom (df)

 

Mean Squares

(MS)

 

F

Between treatments

2380.4

2

1190.2

21.1

Error or residual

846.2

15

56.4

 

Total

3226.6

17

 

 

Group of answer choices
We reject  H0 because 21.1 ≥ 3.68. We have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments.
We reject  H0 because 21.1 ≥ 3.29. We have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments.
We reject  H0 because 21.1 ≥ 3.68. We do not have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments.
We do not reject  H0 because 21.1 ≥ 3.68. We have statistically significant evidence at α = 0.05 to show that there is a difference in mean systolic blood pressure among treatments.
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