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Some standard electrode potentials include Cut + e- → Cu (s) E° = 0.520 V Cu2+ + e- → Cut Eº = 0.159 V Cu2+ + 2e- → Cu (s) Eº = 0.340 V Cu2+ + 2CN + e- → [Cu(CN)₂] EO = 1.12 V Use the information above to calculate the formation constant for [Cu(CN)₂], which is the equilibrium constant for the reaction: Cut + 2CN [Cu(CN)₂] Include two significant figures in your answer. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10

Some standard electrode potentials include Cut + e- → Cu (s) E° = 0.520 V Cu2+ + e- → Cut Eº = 0.159 V Cu2+ + 2e- → Cu (s) Eº = 0.340 V Cu2+ + 2CN + e- → [Cu(CN)₂] EO = 1.12 V Use the information above to calculate the formation constant for [Cu(CN)₂], which is the equilibrium constant for the reaction: Cut + 2CN [Cu(CN)₂] Include two significant figures in your answer. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section19.6: Electrochemistry And Thermodynamics
Problem 1RC
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Some standard electrode potentials include Cut + e- → Cu (s) EO = 0.520 V Cu²+ + e- → Cut Eº = 0.159 V Cu2+ + 2e- → Cu (s) Eº = 0.340 V [Cu(CN)2] EO = 1.12 V Use the information above to calculate the formation constant for [Cu(CN)2], which is the equilibrium constant for the reaction: Cu2+ + 2CN + e- Cut + 2CN [Cu(CN)2] → 4 Include two significant figures in your answer. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10
Transcribed Image Text:Some standard electrode potentials include Cut + e- → Cu (s) EO = 0.520 V Cu²+ + e- → Cut Eº = 0.159 V Cu2+ + 2e- → Cu (s) Eº = 0.340 V [Cu(CN)2] EO = 1.12 V Use the information above to calculate the formation constant for [Cu(CN)2], which is the equilibrium constant for the reaction: Cu2+ + 2CN + e- Cut + 2CN [Cu(CN)2] → 4 Include two significant figures in your answer. Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10
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