Me+ (aq) + N(s)→ N²+ (aq) +M(s)*The standard reduction potentials are:Me+ (aq) + ae¯ → M(s)e= 0.400 VN2+ (ag) + 2 e N(s) e = 0.240 VThe cell contains 0.14 MN* and produces a voltage of 0.180 V. If the concentration of Mª+ is such that the value of the reaction quotient Q is 9.32 × 10-3, calculate [M+].[M*] -[MCalculate wmax for this electrochemical cell.WmaxkJ

The given half reactions are The Nernst equation for (1) is The Nernst equation for (2) is For…

Met (aq)+N(s) - N+ (aq) + M(s)' The standard reduction potentials are: M+ (aq) + ae M(s) e =0.400 V N2+ (ag) + 2 e N(s) e = 0.240 V The cell contains 0.14 MN and produces a voltage of 0.180 V. If the concentration of M+ is such that the value of the reaction quotient Q is 9.32 x 103, calculate [M+]. [M**]-[ M Calculate wmax for this electrochemical cell. Wmax= kJ

Met (aq)+N(s) - N+ (aq) + M(s)' The standard reduction potentials are: M+ (aq) + ae M(s) e =0.400 V N2+ (ag) + 2 e N(s) e = 0.240 V The cell contains 0.14 MN and produces a voltage of 0.180 V. If the concentration of M+ is such that the value of the reaction quotient Q is 9.32 x 103, calculate [M+]. [M**]-[ M Calculate wmax for this electrochemical cell. Wmax= kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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eq req *3 Use the References to access important values if needed for this question. Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: 2H+ (aq) + Fe(s)→ H₂ (s) + Fe²+ (aq) H₂ (8) E Fe(s) E E 2H+ (aq) +2e Fe2+ (aq) +2e -> AGO kj K for this reaction would be Submit Answer $ 4 R % 5 Retry Entire Group 9 more group attempts remaining = 0.000 V red=-0.440 V T red e than one. Cengage Learning Cengage Technical Support 6 MacBook Pro Y & U * 00 8 1 ( 9 K 0 0 Previous Email Instructo P
Sn(s) | Sn2+ (aq, 1.8 M) || Agt(aq, 0.055 M) | Ag(s) Consider the cell notation of a galvanic cell given above and the following reduction potentials: Sn- (aq) + 2e- → Sn(s) E° = -0.14 V Ag (aq) + e- → Agis) ED=0.80 V 1. The number of electron transferred in the net reaction is [Select] 2. The E is [Select] 3. The value for Q is (Select] 4. The cell potential for the cell is [Select] V.
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