I2 (s) + Cu(s) → 21¯ (aq) + Cu²+ (aq) I₂ (s) + 2e¯ → 21¯ (aq) Cu²+ Eº : 0.535 V - red (aq) + 2e¯¯ → Cu(s) Fre - : 0.337 V Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be than zero.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Use standard reduction potentials to calculate the equilibrium constant for the
reaction:
2+
I2 (s) + Cu(s) → 21¯ (aq) + Cu²+ (aq)
I₂ (s) + 2e → 21¯ (aq) Eº
red
Cu²+ (aq) + 2e¯ → Cu(s) Eº
red
= 0.535 V
= 0.337 V
=
Hint: Carry at least 5 significant figures during intermediate calculations to avoid
round off error when taking the antilogarithm.
Equilibrium constant at 298 K:
AGO for this reaction would be
than zero.
Transcribed Image Text:Use standard reduction potentials to calculate the equilibrium constant for the reaction: 2+ I2 (s) + Cu(s) → 21¯ (aq) + Cu²+ (aq) I₂ (s) + 2e → 21¯ (aq) Eº red Cu²+ (aq) + 2e¯ → Cu(s) Eº red = 0.535 V = 0.337 V = Hint: Carry at least 5 significant figures during intermediate calculations to avoid round off error when taking the antilogarithm. Equilibrium constant at 298 K: AGO for this reaction would be than zero.
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