Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: 2Ag (aq) + Fe(s) → 2Ag(s) + Fe²+ (aq) - red Ag+ (aq) + e¯ → Ag(s) E 0.799 V Fe2+ (aq) + 2e → Fe(s) E red -0.440 V kJ AGO = K for this reaction would be - than one.
Use standard reduction potentials to calculate the standard free energy change in kJ for the reaction: 2Ag (aq) + Fe(s) → 2Ag(s) + Fe²+ (aq) - red Ag+ (aq) + e¯ → Ag(s) E 0.799 V Fe2+ (aq) + 2e → Fe(s) E red -0.440 V kJ AGO = K for this reaction would be - than one.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![**Title**: Calculating Standard Free Energy Change Using Standard Reduction Potentials
**Content**:
To calculate the standard free energy change (ΔG°) in kJ for the given reaction, use the standard reduction potentials:
**Reaction**:
\[
2\text{Ag}^+ (aq) + \text{Fe}(s) \rightarrow 2\text{Ag}(s) + \text{Fe}^{2+}(aq)
\]
**Reduction Potentials**:
\[
\begin{align*}
\text{Ag}^+ (aq) + e^- & \rightarrow \text{Ag}(s) & E^\circ_{\text{red}} = 0.799 \, \text{V} \\
\text{Fe}^{2+} (aq) + 2e^- & \rightarrow \text{Fe}(s) & E^\circ_{\text{red}} = -0.440 \, \text{V} \\
\end{align*}
\]
To find ΔG°, use the following formula:
\[
\Delta G^{\circ} =
\]
For this reaction, the equilibrium constant (\(K\)) would be [dropdown: greater than or less than] one.
**Diagrams**:
There are no additional graphs or diagrams in this image.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e109430-7b34-4d38-8cab-38f4ccc5aed5%2F3d3e60c0-2387-446b-bcbd-36fc1b72b7d5%2Fz87qozm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title**: Calculating Standard Free Energy Change Using Standard Reduction Potentials
**Content**:
To calculate the standard free energy change (ΔG°) in kJ for the given reaction, use the standard reduction potentials:
**Reaction**:
\[
2\text{Ag}^+ (aq) + \text{Fe}(s) \rightarrow 2\text{Ag}(s) + \text{Fe}^{2+}(aq)
\]
**Reduction Potentials**:
\[
\begin{align*}
\text{Ag}^+ (aq) + e^- & \rightarrow \text{Ag}(s) & E^\circ_{\text{red}} = 0.799 \, \text{V} \\
\text{Fe}^{2+} (aq) + 2e^- & \rightarrow \text{Fe}(s) & E^\circ_{\text{red}} = -0.440 \, \text{V} \\
\end{align*}
\]
To find ΔG°, use the following formula:
\[
\Delta G^{\circ} =
\]
For this reaction, the equilibrium constant (\(K\)) would be [dropdown: greater than or less than] one.
**Diagrams**:
There are no additional graphs or diagrams in this image.
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