Solve the value of x in the expression and express your answer in correct significant figures log ([3.0 x 10-2][2.0 x 104]/ [2.0 x]3) = 1.347 The value of x, in correct significant figures, is
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- Do the following multiplication and division calculations. Give a final answer with the correct number of significant figures and the correct units. Units can cancel or multiply just like number factors. (2.5 x 103 m/s) x (5.00 x 10-6 s) = ?Perform the following calculation and input the answer expressed to the correct number of significant figures. (264.3−258) ÷ 65=_____ I think the answer is 0.09692308 so significant figure is 7?When the calculation (1.0453x10-1.4) x 1.604 is carried out, the number of significant figures in the answer is? O 1 O 2 O 3 O 4 O 5
- (0.41 + 124.9)/1.4 × 10-2 = with correct signifcant figuresConsider the following mathematical expression: (2.4 × 10³) (2.24 × (2.54)³) 0.7217 x = X The answer X should be expressed as significant figures.The quadratic formula is used to solve for x in equations taking the form of a quadratic equation, ax? + bx + c = 0. -b ± b2 – 4ac quadratic formula: x = 2a Solve for x in the following expression using the quadratic formula. 2x2 + 21x – 7.1 = 0 Use at least three significant figures in each answer. x = and x =
- A student sets up the following equation to convert a measurement. (The ? stands for a number the student is going to calculate.) Fill in the missing part of this equation. (0.020 mL) = ? dl. x10 0.0 X 习 μ3.) Perform the following calculations. Express your answers in scientific notation (1 pt each) using the correct number of significant figures. a) (0.000414000) + (7.80 x 10-11) 40 14×1054 7.8 X 10-11 = 0.53 077X10 [5.3077x10 c) (9.612 x 5.00)- 35.20 -4+11 9612x5-35.2 48.06-35.20 $12.95 - (1.286 X10' b) 118 +3020.760 3020.760 + 118.000 13138.760 |scientific No *13138.761 C 7 -0.03906 11 3.906x10A student sets up the following equation to convert a measurement. (The ? stands for a number the student is going to calculate.) Fill in the missing part of this equation. (0.050 ml) = ? kg mol g x10 0 X 3 00 S