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Solve the following beams shown below, 1.) Find the maximum tensile flexural stress and compressive flexural stress; 2.) Find the maximum shear stress 3.) Find the maximum flexural stresses at 3m from the left end of the fibers at the junction of the web and flange; 4.) Find the maximum shear stress at 3m from the left end

Solve the following beams shown below, 1.) Find the maximum tensile flexural stress and compressive flexural stress; 2.) Find the maximum shear stress 3.) Find the maximum flexural stresses at 3m from the left end of the fibers at the junction of the web and flange; 4.) Find the maximum shear stress at 3m from the left end

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Solve the following beams shown below,

1.) Find the maximum tensile flexural stress and compressive flexural stress;

2.) Find the maximum shear stress

3.) Find the maximum flexural stresses at 3m from the left end of the fibers at the junction of the web and flange;

4.) Find the maximum shear stress at 3m from the left end

5.) write a single moment equation for the entire beam: slope and deflection equation;

given for the reactions are on the picture below

ут VA n N 4 B Celasic curve 80mm وع 20 Fam 100m A Tromm Homm 20mm PA 2 kN/m 0 A 10 2m WZ. Sign convention Ⓒ B 4 kN/m O G (₁ 2 kN/m2 3m From Similar Taansle Wz ។ Z 2 دل a Wz = -ve 44 3 Shear 11 b/ the -ve Moment: els tve Sheas calculation: VA = 0 VB = 2x2 = -4 KN V₂ = 2x5 - 1×3× 4 = -16 KN Z + Moment calculation: MA = 0 тв MB = = -2x 2x1 = - 4 kvm Mc = 2x5x12.5 - 1 x = = - 31 KNM SPD A B Straight line parabolic. BMD - parabolic 3 x 1/2 x 3 x 4 x 10 4 x 1 cubic Photos - Sol 4.jpg W + 14 20x 100 x 10 + 20x110x (20+ ¹12) + 20x80x (20 + 110 + 20 ) 20x100 + 20x110 + 20x80 409000 3 = 5800 4T = 20+110+20-%₂ Moment of inestia, along Neutral xx = 100x203 12 + 20x 1103 12 80x203 + 12 Ixx = 43153 225.93 농 70.517 = 79.482 axis + 100x20x (70.517 -10) ² + 20x llox (75-70.517) ² + 80x20x (79.482-10) ² mmt ..
Transcribed Image Text:ут VA n N 4 B Celasic curve 80mm وع 20 Fam 100m A Tromm Homm 20mm PA 2 kN/m 0 A 10 2m WZ. Sign convention Ⓒ B 4 kN/m O G (₁ 2 kN/m2 3m From Similar Taansle Wz ។ Z 2 دل a Wz = -ve 44 3 Shear 11 b/ the -ve Moment: els tve Sheas calculation: VA = 0 VB = 2x2 = -4 KN V₂ = 2x5 - 1×3× 4 = -16 KN Z + Moment calculation: MA = 0 тв MB = = -2x 2x1 = - 4 kvm Mc = 2x5x12.5 - 1 x = = - 31 KNM SPD A B Straight line parabolic. BMD - parabolic 3 x 1/2 x 3 x 4 x 10 4 x 1 cubic Photos - Sol 4.jpg W + 14 20x 100 x 10 + 20x110x (20+ ¹12) + 20x80x (20 + 110 + 20 ) 20x100 + 20x110 + 20x80 409000 3 = 5800 4T = 20+110+20-%₂ Moment of inestia, along Neutral xx = 100x203 12 + 20x 1103 12 80x203 + 12 Ixx = 43153 225.93 농 70.517 = 79.482 axis + 100x20x (70.517 -10) ² + 20x llox (75-70.517) ² + 80x20x (79.482-10) ² mmt ..
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