solution was prepared by mixing 100.0 mL of 4.0 x 10-2 M Fe(NO3); and 100.0 mL of 2.0 × 10-4 M NAOH. 1. What will be the initial concentrations of Fe3* and OH", respectively? 1.0 x 10-4 M & 2.0 × 10-4 M 2.0 x 10-2 M & 1.0 × 10-² M None of the given. 2.0 x 10-2 M & 2.0 × 10-ª M 1.0 x 10-2 M & 2.0 × 10-ª M 2. What will be the ion product, Qgp? 2.0 x 10-4 6.0 x 10-6 1.0 x 10-6 None of the given. 2.0 x 10-14 3. Will Fe(OH); (Kgp = 4.0 x 10-38) precipitate form? Yes, because Kgsp < Qsp Yes, because Kgp > Qsp No, because Kgsp < < Qsp No, because Kgp > Qsp None of the given.

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A solution was prepared by mixing 100.0 mL of 4.0 × 10-2 M Fe(NO3)3 and 100.0 ml of 2.0 x 10-4 M NAOH.
1. What will be the initial concentrations of Fe3* and OH", respectively?
1.0 x 10-4 M & 2.0 x 10-4 M
2.0 x 10-2 M & 1.0 × 10-2 M
None of the given.
2.0 x 10-2 M & 2.0 × 10-4 M
1.0 x 10-2 M & 2.0 x 10-4 M
2. What will be the ion product, Qsp?
2.0 x 10-4
6.0 x 10-6
1.0 x 10-6
None of the given.
2.0 x 10-14
3. Will Fe(OH); (Ksp = 4.0 x 10-38) precipitate form?
Yes, because Ksp < Qsp
Yes, because Ksp > Qsp
No, because Kgsp < Qsp
No, because Ksp > Qsp
None of the given.
Transcribed Image Text:A solution was prepared by mixing 100.0 mL of 4.0 × 10-2 M Fe(NO3)3 and 100.0 ml of 2.0 x 10-4 M NAOH. 1. What will be the initial concentrations of Fe3* and OH", respectively? 1.0 x 10-4 M & 2.0 x 10-4 M 2.0 x 10-2 M & 1.0 × 10-2 M None of the given. 2.0 x 10-2 M & 2.0 × 10-4 M 1.0 x 10-2 M & 2.0 x 10-4 M 2. What will be the ion product, Qsp? 2.0 x 10-4 6.0 x 10-6 1.0 x 10-6 None of the given. 2.0 x 10-14 3. Will Fe(OH); (Ksp = 4.0 x 10-38) precipitate form? Yes, because Ksp < Qsp Yes, because Ksp > Qsp No, because Kgsp < Qsp No, because Ksp > Qsp None of the given.
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