Soay sheep have a polymorphism in the RXFP2 gene that affects horn size. One allele (Ho+) is associated with larger horns, and another allele (Hop) is associated with smaller horns. Males with the Hop allele have a higher probability of survival, while males with the Ho+ allele have greater reproductive success (see table below). As a result of these fitness tradeoffs, heterozygotes have the highest fitness (see table). Survival probability Offspring per male Fitness Ho+ / Ho+ 0.5 2.5 0.6 Ho+ / Hop 0.8 2.5 1.0 Hop / HOP 0.8 1 0.4
please help solve all of them!
a) If the Ho+ allele is at a frequency of 10% in 1,000 newborn males, what is the expected number of males (at birth) with each genotype?
b) How many of the males of each genotype (from part a) survive to adulthood?
c) Of the males that survive to adulthood (from part b), how many offspring do you expect each genotype to contribute to the next generation?
d) What is the expected frequency of the Ho+ allele in the the offspring born in the next generation (from part c).
e) What is the expected equilibrium frequency of the two alleles given the fitness values shown in the table above and then what is the marginal fitness of the two alleles at the equilibrium frequency?
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