You are a dog breeder and have a client who wants a particular breed of dog with a "poofy tail". Being an experienced dog breeder, you know the "poofy tail" trait is controlled by a dominant allele. You also know the homozygous dominant genotype for this allele doesn't develop past early embryogenesis (i.e. shows lethality). Your client is quite insistent that they want a true-breeding line of "poofy tail" dogs. Given the properties of this gene locus, is this a possibility? O No. Because the trait is homozygous dominant lethal, anytime you try to mate "poofy tail" parents they will only generate normal tail individuals, since inheriting the allele is lethal. O Yes. If you cross two "poofy tail" dogs together, 2/3 of the progeny will have a "poofy tail". You would then cross individuals from this 2/3 group to generate a true-breeding line. O No. Because the trait is homozygous dominant lethal, you will never generate a true homozygote for the trait. The only "poofy tail" individuals that you ever see will be heterozygotes. O Yes. If you cross two "poofy tail" dogs together, 1/3 of the progeny will have a "poofy tail". You would then cross individuals from this 1/3 group to generate a true-breeding line.
You are a dog breeder and have a client who wants a particular breed of dog with a "poofy tail". Being an experienced dog breeder, you know the "poofy tail" trait is controlled by a dominant allele. You also know the homozygous dominant genotype for this allele doesn't develop past early embryogenesis (i.e. shows lethality). Your client is quite insistent that they want a true-breeding line of "poofy tail" dogs. Given the properties of this gene locus, is this a possibility? O No. Because the trait is homozygous dominant lethal, anytime you try to mate "poofy tail" parents they will only generate normal tail individuals, since inheriting the allele is lethal. O Yes. If you cross two "poofy tail" dogs together, 2/3 of the progeny will have a "poofy tail". You would then cross individuals from this 2/3 group to generate a true-breeding line. O No. Because the trait is homozygous dominant lethal, you will never generate a true homozygote for the trait. The only "poofy tail" individuals that you ever see will be heterozygotes. O Yes. If you cross two "poofy tail" dogs together, 1/3 of the progeny will have a "poofy tail". You would then cross individuals from this 1/3 group to generate a true-breeding line.
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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Can you please help these two same problem that relate to each other?
Transcribed Image Text:Given the previously mentioned scenario, suppose you mate two
"poofy tail" dogs. What is the probability that they will have a female
puppy that is a “poofy tail"?
1/3
1/9
1/6
O 2/3
Transcribed Image Text:You are a dog breeder and have a client who wants a particular breed
of dog with a "poofy tail". Being an experienced dog breeder, you know
the "poofy tailr trait is controlled by a dominant allele. You also know
the homozygous dominant genotype for this allele doesn't develop past
early embryogenesis (i.e. shows lethality). Your client is quite insistent
that they want a true-breeding line of "poofy tail" dogs. Given the
properties of this gene locus, is this a possibility?
O No. Because the trait is homozygous dominant lethal, anytime
you try to mate "poofy tail" parents they will only generate normal
tail individuals, since inheriting the allele is lethal.
O Yes. If you cross two "poofy tail" dogs together, 2/3 of the
progeny will have a "poofy tail". You would then cross individuals
from this 2/3 group to generate a true-breeding line.
O No. Because the trait is homozygous dominant lethal, you will
never generate a true homozygote for the trait. The only "poofy
tail" individuals that you ever see will be heterozygotes.
O Yes. If you cross two "poofy tail" dogs together, 1/3 of the
progeny will have a "poofy tail". You would then cross individuals
from this 1/3 group to generate a true-breeding line.
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