smart phone manufacturer is interested in constructing a 90% confidence interval for the proportion of smart phones that break before the warranty expires. 84 of the 1700 randomly selected smart phones broke before the warranty expired. Round answers to 4 decimal places where possible.
Q: A survey of 800 women shoppers found that 17% of them shop on impulse what is the 98% confidence…
A: Sol:- To calculate the 98% confidence interval for the proportion of women shoppers who shop on…
Q: A poll showed that 48 out of 120 randomly chosen graduates of AUAF work in the government. What is…
A: The confidence interval is calculated using the sample statistic, critical value and the standard…
Q: In a sample of 120 adults, 114 had children. Construct a 99% confidence interval for the true…
A:
Q: A random sarmple of ni = 268 people who live in a city were selected and 120 identified as a "dog…
A: Given n1=268, X1=120, n2=117, X2=59
Q: In a sample of 120 adults, 102 had children. Construct a 99% confidence interval for the true…
A: Sample size n=120Favorable cases x=102Sample proportion p^=x/n=102/120=0.85
Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…
A: The sample size, i.e., the sampled number of adults, n=350.The sampled number of adults with…
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Q: In a sample of 270 adults, 151 had children. Construct a 90% confidence interval for the true…
A: Given that Sample size n =270 Favorable cases x =151 Sample proportion p^=x/n =151/270 =0.5593
Q: A bank randomly selected 253 checking account customers and found that 115 of them also had savings…
A: Given information: It is given that a bank randomly selected 253 checking account customers and…
Q: An accounting firm has 1,220 clients. From a random sample of 122 clients, 110 indicated very high…
A: From the given information, the sample size is 122 clients. Among 122 clients, 110 indicated very…
Q: Out of a random sample of 60 freshman at State University, 25 students have declared a major. Find a…
A: Given, Out of a random sample of 60 freshman at State University, 25 students have declared a major.…
Q: An accounting firm has 1,190 clients. From a random sample of 119 clients, 108 indicated very high…
A: Given:
Q: A report statesb that 33% of home owners had a vegetable garden. how large a sample is needed to…
A: p=33%=0.33, E=5%=0.05
Q: A market research firm is hired to estimate the percent of adults living in a large city who have…
A: Givenn=450x=387p^=xn=387450=0.86α=1-0.99=0.01α2=0.005zα2=z0.005=2.5758 (from z table)
Q: In a sample of 290 adults, 191 had children. Construct a 95% confidence interval for the true…
A: 0.604 < p < 0.713 Explanation:Approach to solving the question:To construct a 95% confidence…
Q: A report statesb that 44% of home owners had a vegetable garden. how large a sample is needed to…
A: Answer: Using the given data, A report stated that 44% of home owners had a vegetable garden, P =…
Q: In a sample of 270 adults, 173 had children. Construct a 99% confidence interval for the true…
A: The sample size n= 270. The sample proportion is 173/270. The absolute value of Zα/2 is 2.5758 using…
Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…
A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…
Q: In a sample of 360 adults, 245 had children. Construct a 99% confidence interval for the true…
A:
Q: In a sample of 290 adults, 261 had children. Construct a 95% confidence interval for the true…
A: Given : Sample Size, n = 290 Number of successes, x = 261
Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…
A: Given information
Q: In a sample of 350 adults, 277 had children. Construct a 99% confidence interval for the true…
A: Sample size, Number of adults having children, Confidence level is .
Q: Blood pressure is distribued Normally, with a mean of 85 mm and a standard deviation of 20 mm. As a…
A: Given,mean(μ)=85standard deviation(σ)=20sample size(n)=100
Q: In a survey of 3235 adults 1499 say they have started paying bills online in the last year. A 99%…
A: Solution: Let X be the number of adults say they have started paying bills online in the last year…
Q: Out of a sample of 200 adults aged 18 to 30, 70 still lived with their parents. Based or confidence…
A: Sample size n=200Favorable cases x=70Sample proportion p^=x/n=70/200=0.35
Q: In a sample of 300 adults, 267 had children. Construct a 90% confidence interval for the true…
A: To construct a 90% confidence interval for the population proportion, we'll use the formula for the…
Q: A random sample of n1 = 258 people who live in a city were selected and 74 identified as a "dog…
A: given data n1 =258 x1 = 74p^1 = x1n1 = 74258 = 0.2868 n2 = 102 x2 = 63 p^2 = x2n2 = 63102 =…
Q: A survey found that 611 out of 663 college graduates cannot correctly spell the word aluminum. Find…
A: Given that A survey found that 611 out of 663 college graduates cannot correctly spell the word…
Q: How large a sample is needed to estimate the true proportion of these children getting adequate…
A: It is given that Proportion p = 0.45 Margin of error E = 0.025 Level of confidence = 0.99 The…
Q: In a science fair project, Emily conducted an experiment in which she tested professional touch…
A: Given data, n=330 x=155 sample proportion p=x/n =155/330=0.47 z-value at 95% confidence is zc=1.96
Q: UC Berkeley randomly selects 100 students to represent them on the World Universities Congress next…
A: UC Berkeley randomly selects 100 students to represent them on the World Universities Congress next…
Q: 4- Dissolved oxygen concentrations were measured at 8 different points in a reservoir and…
A: Assume a random variable X to represent the considered oxygen concentrations. Determine the sample…
Q: A market research firm is hired to estimate the percent of adults living in a large city who have…
A: Here, we have to compute 90% confidence interval for the true proportion of adult residents of this…
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Q: Can you please write B up in writing as it is incorrect but I think it's because it's been converted…
A: f(x) = 3(x-1)^2, 0<x<1
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A:
Q: Nearly one-half of Americans ages 25 to 29 are unmarried. How large a sample is necessary to…
A: The provided information is The margin of error is E=0.02 α=0.05 The critical value is zc=1.96…
Q: In a sample of 460 adults, 281 had children. Construct a 90% confidence interval for the true…
A:
Q: A random sample of n₁ = 261 people who live in a city were selected and 107 identified as a "dog…
A: Suppose p1 is the true population proportion of people that live in the city who identify as a “dog…
Q: A random sample of n1n1 = 236 people who live in a city were selected and 90 identified as a "dog…
A: The sample proportions are Critical values: By using the standard normal table of Z, the critical…
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- A random sample of 100 employees at a company shows that 62 are female. Form a 90% confidence interval for the proportion of all employees who are female. The interval is 0.62 what margin of error? Round your answer to 3 decimal places.A random sample of n₁ = 269 people who live in a city were selected and 88 identified as a "dog person." A random sample of n2 = 90 people who live in a rural area were selected and 70 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < P1 P2 <A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?
- In a random sample of 296 people, 179 said that they watched educational television. Find the upper bound limit of the 95% confidence interval of the true proportion of people who watched educational television. Round your answer to 3 decimal places.In a science fair project, Emily conducted an experiment in which she tested professional touch therapists to see if they could sense her energy field. She flipped a coin to select either her right hand or her left hand, and then she asked the therapists to identify the selected hand by placing their hand just under Emily's hand without seeing it and without touching it. Among 337 trials, the touch therapists were correct 163 times. Using Emily's sample results, construct a 95% confidence interval estimate of the proportion of correct responses made by touch therapists. (round to 3 decimal places)We randomly sample 600 people in a specific town. 342 of them like cats. Based on this, construct a 95% confidence interval for the true population proportion of people in this town who like cats. Give your answers as decimals, rounded to four places.
- A random sample of n1n1 = 235 people who live in a city were selected and 79 identified as a "dog person." A random sample of n2n2 = 93 people who live in a rural area were selected and 67 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < p1−p2<During the 2016 season, Lauren Robinson had 92 at bats and made 36 hits. Calculate a 95% confidence interval for her ABILITY to get hits in that season.The dataset "nurses" is a random sample of 1,000 cases from “Health Care Provider Credential Data” from Washington State Open Data Portal. In the sample, there are 418 CNA's and 278 of the CNA's have expired credentials. Use the statistics from the nurses dataset to answer the following question: "With 90% confidence, what percent of all CNA's on Washington State's healthcare provider list are expired?"
- In a sample of 360 adults, 266 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesIn a sample of 510 adults, 281 had children. Construct a 95% confidence interval for the true population proportion of adults with children. Give your answers as decimals, to three placesRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. FreemanMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman