A bank randomly selected 253 checking account customers and found that 115 of them also had savings accounts at this same bank. Construct a 95% confidence interval for the true proportion of checking account customers who also have savings accounts. (Round your answers to three decimal places.) lower limit       upper limit

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease…

A:

Q: I've asked 91 students on Monday whether they did their homework over the weekend. 20 of them said…

A:

Q: In a sample of 460 adults, 262 had children. Construct a 95% confidence interval for the true…

A: Provided information: Total number of adults = 460 and 262 had children 95% confidence level

Q: survey to determine if the percentage of adults who use social media has changed from 52%, which was…

A: The sample proportion is computed as follows, The critical value for 96% confidence level, i.e.,…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Given data, n=152 x=101 p=x/n =0.664 The 95% CI is Zc=1.96

Q: In a recent poll, 410 people were asked if they liked dogs, and 24% said they did. Find the Margin…

A: We have to find margin of error.

Q: A television station surveys 200 customers and finds that 23% of customers watch the evening news.…

A: Given data n=200 p=23% confidence level=99%

Q: A poll of 1060 adults in a country was conducted by telephone. Of those surveyed, 169 had…

A: The sample size is 1060 and number of success is 169.

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: In a class of 37 students, 47% of them said that math was their favorite subject. Construct an 85%…

A: n=37,p^=0.47α=0.15 Solution-: Let, X= Number of students said that math was their favorite subject…

Q: In a survey of 2310 adults, 706 say they believe in UFOS. Construct a 99% confidence interval for…

A: It is given that sample size (n) is 2,310 and x is 706.

Q: In a survey of 2002 adults in a recent​ year, 701 made a New​ Year's resolution to eat healthier.…

A: Given:

Q: T.J. wants to estimate the percentage of college students who have taken out student loans. He…

A:

Q: In a sample of 110 adults, 76 had children. Construct a 95% confidence interval for the true…

A: It is given that, in a sample of 110 adults, 76 had children. It is needed to find a 95% confidence…

Q: In a recent poll, 310 people were asked if they liked dogs, and 40% said they did. Find the Margin…

A: Given data: n = 310p⏞ = 40100=0.40C.I = 99%      =0.99Then, calculate αα = 1-0.99   =0.01Now,…

Q: one with a 95% confidence level and the other with a 99.7% confidence level. Which interval is…

A: Confidence interval is probability, which refers that population parameter will fall within set of…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: business conducts a random sample of 89 of its customers and find that 44 of them think the company…

A:

Q: t poll, 240 people were asked if they liked dogs, and 35% said they did. Find the Margin of Error…

A: Given: n = 240 p^=35%=0.35 The value of z at 95% confidence level is 1.96, which can be obtained by…

Q: Suppose that insurance companies did a survey. They randomly surveyed 450 drivers and found that 310…

A: Obtain 95% confidence interval for the population proportion that claim to always buckle up. The 95%…

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

A:

Q: 980 adults to learn about their gym membership. The results showed that 574 of the respondents lack…

A: The random variable X follows normal distribution. We have to construct 95% confidence interval for…

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: Out of 600 people sampled, 240 have shopped online. Based on this, construct a 90% confidence…

A: Find z-critical value:…

Q: You want to determine if the proportion of people who will vote for the president next year has…

A:

Q: In a random sample of 250 high school students, it was found that 85.2% (213) of them later…

A:

Q: In a recent poll, 190 people were asked if they liked dogs, and 81% said they did. Find the Margin…

A:

Q: A recent survey conducted in a nearby town showed that 791 out of 1,495 people do most their holiday…

A: Here, the sample proportion is =7911495=0.5291 Now, for 90% confidence z=1.645

Q: Construct a 95% confidence interval for the true proportion of checking account customers who also…

A:

Q: In a sample of 480 adults, 384 had children. Construct a 99% confidence interval for the true…

A: The random variable adults with children follow normal distribution. We have to construct 99%…

Q: Out of 500 people sampled, 145 received flu vaccinations this year. Based on this, construct a 90%…

A: We have given that  Sample size n=500 , favorable cases x=145 90% confidence interval  Sample…

Q: You are interested in constructing a 99% confidence interval for the proportion of all caterpillars…

A: Given n=417 X=45

Q: you want to find out the percent of people who use an iPhone so you survey 120 random adults of whom…

A:

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.