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SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm o 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm2 C. 23 490 mm? b. 29750 mm? d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? c. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. a. 4698.00 kN b. 4654.39 kN C. 4610.78 kN d. 6706.59 kN

SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm o 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm2 C. 23 490 mm? b. 29750 mm? d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? c. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. a. 4698.00 kN b. 4654.39 kN C. 4610.78 kN d. 6706.59 kN

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm O 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm² C. 23 490 mm? b. 29750 mm² d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? C. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN
Transcribed Image Text:SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm O 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm² C. 23 490 mm? b. 29750 mm² d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? C. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN
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