SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm o 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm2 C. 23 490 mm? b. 29750 mm? d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? c. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. a. 4698.00 kN b. 4654.39 kN C. 4610.78 kN d. 6706.59 kN
SITUATION III: The cross section of a tension member is shown below: Use Fy=275 MPa, Fu=400 MPa. 25 350 16 mm o 30 25 350 12. Compute for the gross area of the cross section. a. 28 000 mm2 C. 23 490 mm? b. 29750 mm? d. 23000 mm? 13. Compute for the allowable tensile capacity due to yielding. a. 4698.00 kN b. 4654.39 kN - C. 4610.78 kN d. 6706.59 kN 14. Compute for effective net area if shear lag factor is 0.90. Diameter of holes is 3mm more than that of bolts. a. 28 000 mm? c. 23 490 mm? b. 29750 mm? d. 23000 mm? 15. Compute for the allowable tensile capacity due to rupture. b. 4654.39 kN d. 6706.59 kN a. 4698.00 kN C. 4610.78 kN 16. Compute for the safe load that could be carried by the tension member. a. 4698.00 kN b. 4654.39 kN C. 4610.78 kN d. 6706.59 kN
Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
5th Edition
ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter12: Electric Current And Related Variables In Engineering
Section12.2: Electrical Circuits And Components
Problem 6BYG
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