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Silver chloride, AgCl, is known to be a sparingly soluble salt in water, and this is supported by the fact that the cell potential for the dissolution process, AgCl (s) Ag+ (aq) + C (aq), is -0.481 V. Determine how this cell potential is affected when ammonia, NH3, is added by evaluating the cell potential (in V) for the reaction AgCl (s) + 2 NH3 (aq) = Ag(NH3)2+ (aq) + Cl- (aq) Use the Table of Standard Reduction Potentials linked here.

Silver chloride, AgCl, is known to be a sparingly soluble salt in water, and this is supported by the fact that the cell potential for the dissolution process, AgCl (s) Ag+ (aq) + C (aq), is -0.481 V. Determine how this cell potential is affected when ammonia, NH3, is added by evaluating the cell potential (in V) for the reaction AgCl (s) + 2 NH3 (aq) = Ag(NH3)2+ (aq) + Cl- (aq) Use the Table of Standard Reduction Potentials linked here.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Silver chloride, AgCl, is known to be a sparingly soluble salt in water, and this is supported by the fact that the cell potential for the dissolution process, AgCl (s) = Ag+ (aq) + Cl¯ (aq), is −0.481 V. Determine how this cell potential is affected when ammonia, NH3, is added by evaluating the cell potential (in V) for the reaction AgCl (s) + 2 NH3 (aq) ⇒ Ag(NH3)2+ (aq) + Cl¯ (aq) Use the Table of Standard Reduction Potentials linked here.
Transcribed Image Text:Silver chloride, AgCl, is known to be a sparingly soluble salt in water, and this is supported by the fact that the cell potential for the dissolution process, AgCl (s) = Ag+ (aq) + Cl¯ (aq), is −0.481 V. Determine how this cell potential is affected when ammonia, NH3, is added by evaluating the cell potential (in V) for the reaction AgCl (s) + 2 NH3 (aq) ⇒ Ag(NH3)2+ (aq) + Cl¯ (aq) Use the Table of Standard Reduction Potentials linked here.
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